Question

我正在尝试针对W3C XML Schema验证XML。

以下代码执行作业并报告发生错误的时间。但是我无法得到错误的行号。它总是返回-1。

有没有简单的方法来获取行号？

import java.io.File;

import javax.xml.XMLConstants;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.Source;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;

import org.w3c.dom.Document;
import org.xml.sax.SAXParseException;

    public class XMLValidation {

        public static void main(String[] args) {

            try {
                DocumentBuilder parser = DocumentBuilderFactory.newInstance().newDocumentBuilder();
                Document document = parser.parse(new File("myxml.xml"));

                SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
                Source schemaFile = new StreamSource(new File("myschema.xsd"));

                Schema schema = factory.newSchema(schemaFile);

                Validator validator = schema.newValidator();

                validator.validate(new DOMSource(document));

            } catch (SAXParseException e) {
                System.out.println(e.getLineNumber());
                e.printStackTrace();

            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }

Answer 1

我发现了这个

http://www.herongyang.com/XML-Schema/Xerces2-XSD-Validation-with-XMLReader.html

似乎提供了以下详细信息（包括行号）

Error:
   Public ID: null
   System ID: file:///D:/herong/dictionary_invalid_xsd.xml
   Line number: 7
   Column number: 22
   Message: cvc-datatype-valid.1.2.1: 'yes' is not a valid 'boolean' 
   value.

使用此代码：

/**
 * XMLReaderValidator.java
 * Copyright (c) 2002 by Dr. Herong Yang. All rights reserved.
 */
import java.io.IOException;
import org.xml.sax.XMLReader;
import org.xml.sax.helpers.DefaultHandler;
import org.xml.sax.helpers.XMLReaderFactory;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
class XMLReaderValidator {
   public static void main(String[] args) {
      String parserClass = "org.apache.xerces.parsers.SAXParser";
      String validationFeature 
         = "http://xml.org/sax/features/validation";
      String schemaFeature 
         = "http://apache.org/xml/features/validation/schema";
      try {
         String x = args[0];
         XMLReader r = XMLReaderFactory.createXMLReader(parserClass);
         r.setFeature(validationFeature,true);
         r.setFeature(schemaFeature,true);
         r.setErrorHandler(new MyErrorHandler());
         r.parse(x);
      } catch (SAXException e) {
         System.out.println(e.toString()); 
      } catch (IOException e) {
         System.out.println(e.toString()); 
      }
   }
   private static class MyErrorHandler extends DefaultHandler {
      public void warning(SAXParseException e) throws SAXException {
         System.out.println("Warning: "); 
         printInfo(e);
      }
      public void error(SAXParseException e) throws SAXException {
         System.out.println("Error: "); 
         printInfo(e);
      }
      public void fatalError(SAXParseException e) throws SAXException {
         System.out.println("Fattal error: "); 
         printInfo(e);
      }
      private void printInfo(SAXParseException e) {
         System.out.println("   Public ID: "+e.getPublicId());
         System.out.println("   System ID: "+e.getSystemId());
         System.out.println("   Line number: "+e.getLineNumber());
         System.out.println("   Column number: "+e.getColumnNumber());
         System.out.println("   Message: "+e.getMessage());
      }
   }
}

Answer 2

尝试使用SAXLocator http://download.oracle.com/javase/1.5.0/docs/api/org/xml/sax/Locator.html 解析器不需要提供一个，但如果他们这样做，它应该报告行号

我认为您的代码应包含：

 // this will be called when XML-parser starts reading
    // XML-data; here we save reference to current position in XML:
    public void setDocumentLocator(Locator locator) {
        this.locator = locator;
    }

（见http://www.java-tips.org/java-se-tips/org.xml.sax/using-xml-locator-to-indicate-current-parser-pos.html）

解析器将为您提供一个定位器，然后您可以使用该定位器来获取行号。当发生这种情况时，可能值得打印/调试，看看你是否有一个有效的定位器

Answer 3

替换此行：

validator.validate(new DOMSource(document));

作者

validator.validate(new StreamSource(new File("myxml.xml")));

将让SAXParseException包含行号和列号

Answer 4

假设最终目标是拥有一个经过验证的DOM实例，那么先前的答案将要求XML文档被读取两次-首先进行验证，然后再次构建对象树。如果将文档作为文件路径给出，那很好，但是如果将其作为输入流提供，则将需要某种解决方法，原则上只能读取一次。

一种更有效的替代方法是在构建对象树时使用验证解析器根据架构检查XML文档。请参阅下面的代码，了解如何设置验证模式的DOM分析器：

import java.io.File;
import java.io.FileInputStream;
import java.io.InputStream;

import javax.xml.XMLConstants;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;

import org.w3c.dom.Document;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;

public class XML {
    public static Document load(String xml, String xsd) {
        // The default error handler just prints errors to the standard error output. In
        // order to make the parser interrupt its work once a validation error is found,
        // we need to use a custom handler that throws an exception in response to any
        // reported issues.
        ErrorHandler errorHandler = new ErrorHandler() {
            @Override
            public void error(SAXParseException exception) throws SAXException {
                throw exception;
            }

            @Override
            public void fatalError(SAXParseException exception) throws SAXException {
                throw exception;
            }

            @Override
            public void warning(SAXParseException exception) throws SAXException {
                throw exception;
            }
        };

        try {
            SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
            Schema schema = factory.newSchema(new File(xsd));

            DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
            builderFactory.setNamespaceAware(true);
            builderFactory.setSchema(schema);

            DocumentBuilder builder = builderFactory.newDocumentBuilder();
            builder.setErrorHandler(errorHandler);

            InputStream input = new FileInputStream(xml);
            Document document = builder.parse(input);

            return document;
        }
        catch (SAXParseException e) {
          int row = e.getLineNumber();
          int col = e.getColumnNumber();
          String message = e.getMessage();
          System.out.println("Validation error at line " + row + ", column " + col + ": \"" + message + '"');
        }
        catch (Exception e) {
            e.printStackTrace();
        }

        return null;
    }

    public static void main(String[] args) {
        String xml = args[0];
        String xsd = args[1];

        Document document = load(xml, xsd);
        boolean valid = (document != null);

        System.out.println("Document \"" + xml + "\" is " + (valid ? "" : "not ") + "valid against schema \"" + xsd + '"');
    }
}

Answer 5

你可以抓住SaxException e。然后拨打e.toString()

它会给出类似的东西：

org.xml.sax.SAXParseException; lineNumber：2668151; columnNumber：80;字符序列“]]＆gt;”除非用于标记CDATA部分的结尾，否则不得出现在内容中。

如何在针对XML模式验证XML文件时获取错误的行号

5 个答案: