Question

我有多个if语句用于标题显示。如果该字段为空，我该如何隐藏标题？我知道怎么做更简单！空但不是为了这个。

澄清......

总会有一个“列出”的变量，但并不总是一个“经纪”变量。当“broker”变量为空时，我不希望显示标题。因此，必须检查“经纪人”，如果存在“已列出”变量，则返回空状态。如果“broker”不为空，那么它必须根据“列出”它返回一个特定的标题。

{{1}}

Answer 1

global $post; $listed = get_post_meta($post->ID,'listed',true);
if(isset($listed)&&$listed!=""){
    if( $listed == 'Sold' ) { echo ' <div class="more-information">Sold By</div><li> [broker] '; }
    else if( $listed == 'For Sale' ) { echo ' <div class="more-information">Contact Information </div><li> [broker]'; }
    else if( $listed == 'Not For Sale' ) { echo ' <div class="more-information">Last Active Agent </div><li> [broker]'; }
    else if( $listed == 'Contingent or Pending Sale' ) { echo ' <div class="more-information">If interested, contact agent for current status. </div><li> [broker]'; }
    else if( $listed == 'Demolished' ) { echo '<li> '; }
    else{
        //Default case i.e. do nothing
        //Nothing here to display
    }
}
else{
    //Default case i.e. do nothing
    //Nothig here
}

你没有默认情况。见上面的代码。您只是使用如果是这样，除了这些条件之外没有定义默认情况。您也可以使用switch ...case语句作为默认条件。

if(condition){
   //do something
}
else if(condition){
   //do something
}
else if(condition){
   //do something
}
else{
   //this is default case if your condition does not true with any of the above if conditions
   //Here in your case will not be anything i.e. dont echo anything
}

Answer 2

您是否尝试过检查变量？

<?php
global $post;
$listed = get_post_meta($post->ID,'listed',true);

if(isset($broker) AND $broker AND $listed)
{
    if( $listed == 'Sold' ) { echo ' <div class="more-information">Sold By</div><li> [broker] '; }
    if( $listed == 'For Sale' ) { echo ' <div class="more-information">Contact Information </div><li> [broker]'; }
    if( $listed == 'Not For Sale' ) { echo ' <div class="more-information">Last Active Agent </div><li> [broker]'; }
    if( $listed == 'Contingent or Pending Sale' ) { echo ' <div class="more-information">If interested, contact agent for current status. </div><li> [broker]'; }
    if( $listed == 'Demolished' ) { echo '<li> '; }
}
else
{
    // Echo nothing
    echo "";
}

Answer 3

这就是修复它的原因。

public function hookDisplayAfterThemeInstallation($params)
{
    $theme_name = $params['theme_name'];
    if ($theme_name != 'mythemename') {
        return false;
    }
    // Enable Move JS to bottom setting
    Configuration::updateValue('PS_JS_DEFER', 1);

    // Optional text or html to display 
    return 'Your settings have been changed';
}

php echo除了如果为空，如何在多个if语句时隐藏？

3 个答案: