所以我正在开发一个可以解决短信通知的应用程序(可能直接将信息发送到收件箱)
我正在使用Lollipop。
那里有代码会使这成为可能吗?
这是我到目前为止所得到的。
FIRST JAVA CLASS
public class NoNotification extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
abortBroadcast();
}
}
第二个JAVA文件
private static final String CHECK_OP_NO_THROW = "checkOpNoThrow";
private static final String OP_POST_NOTIFICATION = "OP_POST_NOTIFICATION";
public static boolean isNotificationEnabled(Context context) {
AppOpsManager mAppOps = (AppOpsManager) context.getSystemService(Context.APP_OPS_SERVICE);
ApplicationInfo appInfo = context.getApplicationInfo();
String pkg = context.getApplicationContext().getPackageName();
int uid = appInfo.uid;
Class appOpsClass = null; /* Context.APP_OPS_MANAGER */
try {
appOpsClass = Class.forName(AppOpsManager.class.getName());
Method checkOpNoThrowMethod = appOpsClass.getMethod(CHECK_OP_NO_THROW, Integer.TYPE, Integer.TYPE, String.class);
Field opPostNotificationValue = appOpsClass.getDeclaredField(OP_POST_NOTIFICATION);
int value = (int)opPostNotificationValue.get(Integer.class);
return ((int)checkOpNoThrowMethod.invoke(mAppOps,value, uid, pkg) == AppOpsManager.MODE_ALLOWED);
} catch (ClassNotFoundException e) {
e.printStackTrace();
} catch (NoSuchMethodException e) {
e.printStackTrace();
} catch (NoSuchFieldException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
}
return false;
}
}
我可能错过了一些权限吗?
感谢。