用于2个值查找的SQL案例

Question

我正在尝试使用Case语句来查找表格，如果表格显示了舞台06和舞台11，那么如果仅显示舞台06则将其视为修改后，则不会修改。

我目前的代码是：

DECLARE

@DATE1 DATETIME = '04/01/2017',
@DATE2 DATETIME = '04/30/2017',
@RAISEDBY VARCHAR (10) = 'CAROLIND'

SELECT DISTINCT

J.[RAISED-BY],
J.[JOB-NO],
J.[JOB-STATUS],
J.[DATE-LOGGED],
J.[CURRENT-STAGE-CODE],
J.[ORIG-LOGGED-VALUE] AS "LOGGED-VALUE",
J.[TOTAL-VALUE],
J.[SHORT-DESCRIPTION],
J.[CONTRACTOR],
C.[DESCRIPTION],
CASE 
    WHEN SH.[STAGE-CODE] = '06' AND SH.[STAGE-CODE] = '11' THEN 'YES'
    ELSE 'NO'
    END AS "AMENDED"

FROM

DBO.[JOB] AS J
LEFT OUTER JOIN
DBO.[CONT] as C ON C.CONTRACTOR = J.CONTRACTOR
LEFT OUTER JOIN
DBO.[JOB-STAGE-HISTORY] AS SH ON SH.[JOB-NO] = J.[JOB-NO]

WHERE

J.[DATE-LOGGED] BETWEEN @DATE1 AND @DATE2
AND
J.[RAISED-BY] = @RAISEDBY
AND
SH.[JOB-NO] = 'W0423540'

ORDER BY

J.[RAISED-BY],
J.[JOB-NO]

当查询为'YES'时，此查询当前返回'NO'，因为在Job Stage History表中有一行06和11。

由于

查询结果

工作阶段历史表

Answer 1

您的CASE正在检查记录中的单个字段是否等于两个不同的值，这些值始终为false。你想要的是检查JOB-STAGE-HISTORY表中是否存在两个不同的行（ 06 行， 11 行）。尝试用{：

替换CASE

case when (select count(distinct j.[STAGE-CODE]) 
           from [JOB-STAGE-HISTORY] j 
           where j.[JOB-NO] = sh.[JOB-NO] 
           and j.[STAGE-CODE] in ('06','11')) = 2 
then 'YES' else 'NO' end AMENDED

Answer 2

不确定以下内容是否会获取结果。

修改/添加连接条件，如下所示。

LEFT OUTER JOIN
DBO.[JOB-STAGE-HISTORY] AS SH ON SH.[JOB-NO] = J.[JOB-NO]
and sh.[STAGE-CODE] = 06

left outer join
dbo.[JOB-STAGE-HISTORY] AS SH1 on SH1.[JOB-NO] = SH.[JOB-NO]
and SH1.[STAGE-CODE] = 11

添加连接条件后，更改case语句如下。

CASE 
    WHEN SH1.[STAGE-CODE] is null then 'No' else 'Yes' end.

答案是基于您对问题的假设。

Answer 3

由于涉及到两者，所提供的答案都很有效。我花了一些时间来研究这个挑战，并相信这可能是另一种解决方法：

SELECT DISTINCT

J.[RAISED-BY],
J.[JOB-NO],
J.[JOB-STATUS],
J.[DATE-LOGGED],
J.[CURRENT-STAGE-CODE],
J.[ORIG-LOGGED-VALUE] AS "LOGGED-VALUE",
J.[TOTAL-VALUE],
J.[SHORT-DESCRIPTION],
J.[CONTRACTOR],
C.[DESCRIPTION],
SH.[JOB-AMENDED]

FROM

DBO.[JOB] AS J
LEFT OUTER JOIN
DBO.[CONT] as C ON C.CONTRACTOR = J.CONTRACTOR
RIGHT OUTER JOIN
(SELECT 
       [JOB-NO], 
       CASE WHEN MAX([STAGE-CODE]) = ('11') THEN 'YES' ELSE 'NO' END AS "JOB-AMENDED"
FROM
DBO.[JOB-STAGE-HISTORY] 
WHERE [STAGE-CODE] IN ('06','11')
GROUP BY [JOB-NO]) AS SH ON J.[JOB-NO] = SH.[JOB-NO] 

WHERE

J.[DATE-LOGGED] BETWEEN @DATE1 AND @DATE2
AND
J.[RAISED-BY] = @RAISEDBY

它肯定会提供所需的结果以及提供的其他答案。