Question

我的原生查询存在问题。

我有：

@Query(value="SELECT * from orders where orders.house in ((:houseArray))", nativeQuery = true)
    List<Order> findByHouseId(@Param("houseArray") List<Long> houseArray);

当我尝试执行时，我得到以下内容：

2017-04-18 14:19:49,736 DEBUG org.hibernate.SQL: SELECT * from orders where orders.house in ((?, ?, ?, ?, ?))
2017-04-18 14:19:49,737 TRACE o.h.t.d.s.BasicBinder: binding parameter [2] as [BIGINT] - [4]
2017-04-18 14:19:49,737 TRACE o.h.t.d.s.BasicBinder: binding parameter [3] as [BIGINT] - [5]
2017-04-18 14:19:49,737 TRACE o.h.t.d.s.BasicBinder: binding parameter [1] as [BIGINT] - [3]
2017-04-18 14:19:49,737 TRACE o.h.t.d.s.BasicBinder: binding parameter [4] as [BIGINT] - [6]
2017-04-18 14:19:49,737 TRACE o.h.t.d.s.BasicBinder: binding parameter [5] as [BIGINT] - [7]
2017-04-18 14:19:49,738 ERROR o.h.e.j.s.SqlExceptionHelper: ERROR: operator does not exist: bigint = record
  Hint: No operator matches the given name and argument type(s). You might need to add explicit type casts.
  Position: 49
2017-04-18 14:19:49,756 ERROR o.a.c.c.C.[.[.[.[dispatcherServlet]: Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not extract ResultSet] with root cause
org.postgresql.util.PSQLException: ERROR: operator does not exist: bigint = record
  Hint: No operator matches the given name and argument type(s). You might need to add explicit type casts.

但是，如果我在控制台中运行以下查询：

SELECT * from orders where orders.house in (1,15,2,4,5,3,6,7);

返回正确的订单列表。

我该如何解决这个问题？

Answer 1

尝试从((:houseArray))中移除一组括号，使其看起来像这样：

@Query(value="SELECT * from orders where orders.house in (:houseArray)", nativeQuery = true)
List<Order> findByHouseId(@Param("houseArray") List<Long> houseArray);

(value, value, value)是一条记录，因此当您执行column in ((value, value, value))时，您会将列与记录进行比较。

本机查询无法在hibernate中工作

1 个答案: