Question

我做了一个有3个表的查询：1表示当前年份，去年和国家名称

正如您所看到的，今年和去年的结果是相同的，这就是问题所在。我想用得像。我想用一个当前年份和一个去年一个查询。

我可以在去年使用此YEAR(o.date_add) = YEAR(NOW() - INTERVAL 1 YEAR)

从今年起，我可以使用它，例如：YEAR(o.date_add) = YEAR(CURRENT_DATE())

我的查询：

SELECT
    IFNULL(SUM(DISTINCT o.total_paid_tax_excl), 0)  AS CurrentYEAR,
    IFNULL(SUM(DISTINCT o.total_paid_tax_excl), 0)  AS LastYEAR,
    IFNULL(CONCAT(l.name), 0) AS name
FROM
    expoled.ps_orders o
        LEFT JOIN
    expoled.ps_address a ON o.id_address_delivery = a.id_address
        INNER JOIN
    expoled.ps_country c ON a.id_country = c.id_country
        INNER JOIN
    expoled.ps_country_lang l ON c.id_country = l.id_country
WHERE
    l.id_lang = 7
        AND o.current_state IN (3 , 4, 5, 9, 13, 15, 20, 22, 23, 24, 25, 121)
        AND l.name NOT IN ('Netherlands')
GROUP BY (l.name)

我可以进行单独查询，但我想在1个查询中如何实现这一点？我确实尝试了Union，但结果保持不变。

我想要这样（这个不起作用!!仅举例如[photoshop] ddd

我想我需要更改查询的这一部分

SELECT
    IFNULL(SUM(o.total_paid_tax_excl), 0)  AS CurrentYEAR,
    IFNULL(SUM(o.total_paid_tax_excl), 0)  AS LastYEAR,
    IFNULL(CONCAT(l.name), 0) AS name
FROM

并将其添加到我的查询

对于CurrentYEAR = YEAR(o.date_add) = YEAR(CURRENT_DATE())

对于LastYEAR = YEAR(o.date_add) = YEAR(NOW() - INTERVAL 1 YEAR)

Answer 1

我认为你可以尝试这样的事情（我为带有SUM的字段和Where条件添加CASE以仅提取相关年份）：

SELECT
    IFNULL(SUM(  CASE WHEN YEAR(CURRENT_DATE)-YEAR(o.date_date) =0 THEN o.total_paid_tax_excl ELSE 0 END), 0)  AS CurrentYEAR,
    IFNULL(SUM( CASE WHEN YEAR(CURRENT_DATE)-YEAR(o.date_date) =1 THEN o.total_paid_tax_excl ELSE 0 END), 0)  AS LastYEAR,
    IFNULL(CONCAT(l.name), 0) AS name
FROM
    expoled.ps_orders o
        LEFT JOIN
    expoled.ps_address a ON o.id_address_delivery = a.id_address
        INNER JOIN
    expoled.ps_country c ON a.id_country = c.id_country
        INNER JOIN
    expoled.ps_country_lang l ON c.id_country = l.id_country
WHERE
    l.id_lang = 7
        AND o.current_state IN (3 , 4, 5, 9, 13, 15, 20, 22, 23, 24, 25, 121)
        AND l.name NOT IN ('Netherlands')
        AND YEAR(o.date_date) IN (YEAR(CURRENT_DATE()), YEAR(CURRENT_DATE)-1)
GROUP BY (l.name)

Answer 2

您可以在if()聚合函数中使用条件表达式（case函数或sum()语句）仅添加符合条件的值：

SELECT
    IFNULL(SUM(DISTINCT if(YEAR(o.date_add) = YEAR(CURRENT_DATE()),o.total_paid_tax_excl, 0)), 0)  AS CurrentYEAR,
    IFNULL(SUM(DISTINCT if(YEAR(o.date_add) = YEAR(CURRENT_DATE())-1,o.total_paid_tax_excl, 0)), 0)  AS LastYEAR,
    IFNULL(l.name, '') AS name
FROM
    expoled.ps_orders o
        LEFT JOIN
    expoled.ps_address a ON o.id_address_delivery = a.id_address
        INNER JOIN
    expoled.ps_country c ON a.id_country = c.id_country
        INNER JOIN
    expoled.ps_country_lang l ON c.id_country = l.id_country
WHERE
    l.id_lang = 7
        AND o.current_state IN (3 , 4, 5, 9, 13, 15, 20, 22, 23, 24, 25, 121)
        AND l.name NOT IN ('Netherlands')
GROUP BY IFNULL(l.name, '')

我还简化了name字段的表达式，并使group by子句与它一致。

我没有更改查询的任何其他部分，但我并不真正同意distinct中的sum()，因为您可以获得与税相同的价值，但这是您的数据

如果您的表的数据比上一年的数据旧，那么请考虑添加where条件来限制运行计算的记录。

SQL在一个查询中生成2种不同的日期类型

2 个答案: