希望使用MSSQL 2008R2按照以下映射执行数据屏蔽:
映射表
A = C
B = A
C = E
1 = 3
2 = 1
3 = 9
原始
ABC123
屏蔽
CAE319
这个想法是使用替换,但第二个替换函数将替换先前替换的值。
select Replace(Replace(Replace(Replace(Replace(REPLACE('ABC123', 'A', 'C'), 'B', 'A'), 'C', 'E'), '1', '3'), '2', '1'), '3', '9')
结果: CAE319
P.S。编辑的值,因为在这种情况下不能使用反向或反向替换
任何想法?
答案 0 :(得分:3)
如果你想要更多的表格方法。
下面有两个代码段,它们将掩盖或取消一个字符串。轻松转换为UDF甚至放在CROSS APPLY
中Declare @Mask table (MapFrom varchar(10),MapTo varchar(10))
Insert into @Mask values
('A','C'),
('B','D'),
('C','E'),
('1','2'),
('2','3'),
('3','9')
Declare @Yourtable table (ID int,SomeCol varchar(max))
Insert Into @Yourtable values
(1,'ABC123')
-- To Mask
Declare @U varchar(max) ='ABC123'
Select NewSting = Stuff((Select ''+S
From (
Select N
,S=IsNull(MapTo,Substring(@U,N,1))
From (Select Top (Len(@U)) N=Row_Number() Over (Order By (Select null)) From master..spt_values) N
Left Join @Mask on Substring(@U,N,1)=MapFrom
) X
Order By N
For XML Path ('')),1,0,'')
-- To UnMask
Declare @M varchar(max) = 'CDE239'
Select NewSting = Stuff((Select ''+S
From (
Select N
,S=IsNull(MapFrom,Substring(@M,N,1))
From (Select Top (Len(@M)) N=Row_Number() Over (Order By (Select null)) From master..spt_values) N
Left Join @Mask on Substring(@M,N,1)=MapTo
) X
Order By N
For XML Path ('')),1,0,'')
答案 1 :(得分:1)
只需更改替换顺序并反转结果
即可select REVERSE( Replace(Replace(Replace(Replace(Replace(REPLACE('321CBA', '3', '9'), '2', '3'), '1', '2'), 'C', 'E'), 'B', 'D'), 'A', 'C'))
结果:
CDE239
编辑:
Declare @Mask table (MapFrom varchar(10),MapTo varchar(10))
Insert into @Mask values
('A','C'),
('B','A'),
('C','E'),
('1','3'),
('2','1'),
('3','9')
DECLARE @pos INT
,@result VARCHAR(100)
,@maskfrom NCHAR(1)
,@mask_to NCHAR(1);
SET @result = 'ABC123';
SET @pos = 1
WHILE @pos < LEN(@result) + 1
BEGIN
SELECT @mask_to = MapTo
FROM @mask
WHERE MapFrom = substring(@result, @pos, 1)
SET @result = STUFF(@result, @pos, 1, @mask_to);
SET @pos = @pos + 1;
END
SELECT @result
<强> RESULT 强>
CAE319