您好我正在使用Xamarin对android进行应用。我编写了一个代码来从WSO2调用API,它返回的答案取决于用户发送的ID。它在内容中返回一个JSON,如下所示:
{ “consumerId”:56704292158, “的categoryId”:1, “categoryDescription”: “佩索阿” “firstName”:“FN”,“lastName”:“姓氏”,“financialDocuments”:[{“financialDocument”:{“documentType”:“Brasil:nºCPF”,“cpf”:199999992}}],“性别“:” M”, “EMAILADDRESS”: “:R **** @ * COM”, “optIns”:[{ “选择启用”:{ “名优产品”: “领事”, “acceptanceStatus”:假}},{ “OPTIN”:{ “名优产品”: “brastemp”, “acceptanceStatus”:真}}], “communicationData”:[{ “communicationInfo”:{ “addressId”:2 **** 03, “PHONENUMBERS”:[{ “phoneNumber的”:{ “PHONETYPE”: “mobilePhone”, “phoneNumber的”:5555555555}}], “的StreetAddress”:“ANY STREET“,”streetNumber“:123,”streetComplement“:null,”streetDistrict“:”ANY TOWN“,”cityName“:”ANY CITY“,”stateCode“:”XX“,”zipCode“:”12345“,” locationReferences “:[{” locationReference “:” 梅尔卡 “}],” COUNTRYCODE “:” ZZ “}},{” communicationInfo “:{” addressId “:2.563244E + 7”,PHONENUMBERS “:[{” phoneNumber的“: {“phoneType”:“mobilePhone”,“phoneNumber”:5555555555}},{“phoneNumber”:{“phoneType”:“homePhone”,“phoneNumber”:555555555}}],“streetAddress”:“ANY STREET”,“ streetNumber“:123,”streetComplement“:”CASA“,”streetDistrict“:”ANY TOWN“,”cityName“:”ANY CITY“,”stateCode“:”XX“,”zipCode“:”12345“,”locationReferences“ :[{“locationReference”:“Ao lado do deposito lua nova”}],“countryCode”:“ZZ”}}]}
我只想从这里得到firstName和lastName字段。我正在尝试将其序列化,但我认为我做错了什么。这是代码
using System;
using Android.App;
using Android.Widget;
using Android.OS;
using RestSharp;
using Newtonsoft.Json;
using Android.Util;
using App4.Resources;
using Newtonsoft.Json.Linq;
namespace App4
{
[Activity(Label = "App4", MainLauncher = true, Icon = "@drawable/icon")]
public class MainActivity : Activity
{
EditText edtcpf;
Button btnConsumer;
TextView txtcpf;
RestRequest cpf { get; set; }
public RestClient consumer { get; set; }
IRestResponse mensagemConsumer;
TextView txtresposta;
RestClient orderId { get; set; }
RestRequest requestorderId { get; set; }
IRestResponse answer { get; set; }
IRestResponse answerorder { get; set; }
TextView txtnome;
public string raika;
private string teamname;
private JToken primeironome;
protected override void OnCreate(Bundle bundle)
{
base.OnCreate(bundle);
// Set our view from the "main" layout resource
SetContentView(Resource.Layout.Main);
btnConsumer = FindViewById<Button>(Resource.Id.btnConsumer);
edtcpf = FindViewById<EditText>(Resource.Id.edtcpf);
txtcpf = FindViewById<TextView>(Resource.Id.txtcpf);
txtresposta = FindViewById<TextView>(Resource.Id.txtresposta);
txtnome = FindViewById<TextView>(Resource.Id.txtNome);
btnConsumer.Click += BtnConsumer_Click;
}
private void BtnConsumer_Click(object sender, EventArgs e)
{
try
{
// API Consumer CPF
consumer = new RestClient("https://qa.api-latam.whirlpool.com/v1.0/consumers");
cpf = new RestRequest("/" + edtcpf.Text, Method.GET);
cpf.AddHeader("Content-Type", "application/json; charset=utf-8");
cpf.AddHeader("Authorization", "Bearer 70197e6c-d81b-384c-bb32-d69e8c10b101");
mensagemConsumer = consumer.Execute(cpf);
string nombre = Convert.ToString(mensagemConsumer.Content);
Nome nome = new Nome();
string json = JsonConvert.SerializeObject(mensagemConsumer.Content, Formatting.Indented);
nome.firstName = mensagemConsumer.Content;
Log.Info("info ",json);
txtresposta.Text = json;
//API Consumer Appliances
orderId = new RestClient("https://qa.api-latam.whirlpool.com/v1.0/consumers/");
requestorderId = new RestRequest("/"+ edtcpf.Text+ "/service-orders", Method.GET);
requestorderId.AddHeader("Content-Type", "application/json; charset=utf-8");
requestorderId.AddHeader("Authorization", "Bearer 70197e6c-d81b-384c-bb32-d69e8c10b101");
answerorder = orderId.Execute(requestorderId);
txtnome.Text = answerorder.Content;
string respostaorder = Convert.ToString(answerorder);
dynamic deserializado = JsonConvert.DeserializeObject(respostaorder);
}
catch (Exception)
{
throw;
}
}
}
}
这是带有get和set
的类using System.Collections.Generic;
using System.Linq;
using System.Text;
using Android.App;
using Android.Content;
using Android.OS;
using Android.Runtime;
using Android.Views;
using Android.Widget;
namespace App4.Resources
{
public class Nome
{
public string firstName { get; set;}
public string lastName { get; set; }
}
}
如何使用依赖于.Text(如edtcpf.Text及其内容)的var的JSON序列化和反序列化?
答案 0 :(得分:0)
首先,你需要检查这是否是一个有效的json。根据我的分析,它有一些错误,如lastName。您可以使用此网站验证https://jsonformatter.curiousconcept.com/
这个json以奇怪的方式构建,但是通过创建它拥有的所有对象,你可以像这样使用它:
using System;
using System.Collections.Generic;
using Newtonsoft.Json;
namespace teste {
class MainClass {
public static void Main(string[] args) {
var jsonString = @"{'consumerId':56704292158, 'categoryId':1, 'categoryDescription': 'Pessoa', 'firstName':'FN','lastName':'Last Name','fiscalDocuments':[{'fiscalDocument':{'documentType':'Brasil: nº CPF','cpf':199999992}}],'gender':'M','emailAddress':'r * ***@*.com','optIns':[{'optIn':{'brandName':'consul','acceptanceStatus':false}},{'optIn':{'brandName':'brastemp','acceptanceStatus':true}}],'communicationData':[{'communicationInfo':{'addressId':'2****03','phoneNumbers':[{'phoneNumber':{'phoneType':'mobilePhone','phoneNumber':5555555555}}],'streetAddress':'ANY STREET','streetNumber':123,'streetComplement':null,'streetDistrict':'ANY TOWN','cityName':'ANY CITY','stateCode':'XX','zipCode':'12345','locationReferences':[{'locationReference':'Mercado'}],'countryCode':'ZZ'}},{'communicationInfo':{'addressId':'2.563244','phoneNumbers':[{'phoneNumber':{'phoneType':'mobilePhone','phoneNumber':5555555555}},{'phoneNumber':{'phoneType':'homePhone','phoneNumber':555555555}}],'streetAddress':'ANY STREET','streetNumber':123,'streetComplement':'CASA','streetDistrict':'ANY TOWN','cityName':'ANY CITY','stateCode':'XX','zipCode':'12345','locationReferences':[{'locationReference':'Ao lado do deposito lua nova'}],'countryCode':'ZZ'}}]}";
JsonSerializerSettings jsonSerializerSettings = new JsonSerializerSettings {
NullValueHandling = NullValueHandling.Ignore,
MissingMemberHandling = MissingMemberHandling.Ignore
};
Pessoa pessoa = JsonConvert.DeserializeObject<Pessoa>(jsonString, jsonSerializerSettings);
Console.WriteLine(pessoa.FirstName);
Console.WriteLine(pessoa.LastName);
}
}
public class Pessoa {
public long ConsumerId { get; set; }
public int CategoryId { get; set; }
public string CategoryDescription { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public List<FiscalDocumentData> FiscalDocuments { get; set; }
public string Gender { get; set; }
public string EmailAddress { get; set; }
public List<OptInData> OptIns { get; set; }
public List<CommunicationData> CommunicationData { get; set; }
}
public class OptInData {
public OptInInfo OptIn { get; set; }
}
public class OptInInfo {
public string BrandName { get; set; }
public bool AcceptanceStatus { get; set; }
}
public class FiscalDocumentData {
public FiscalDocumentInfo FiscalDocument {get; set; }
}
public class FiscalDocumentInfo {
public string DocumentType { get; set; }
public long Cpf { get; set; }
}
public class CommunicationData {
public CommunicationInfo CommunicationInfo { get; set; }
}
public class CommunicationInfo {
public string AddressId { get; set; }
public List<PhoneInfo> PhoneNumbers { get; set; }
public string StreetAddress { get; set; }
public int StreetNumber { get; set; }
public string StreetComplement { get; set; }
public string StreetDistrict { get; set; }
public string CityName { get; set; }
public string StateCode { get; set; }
public string ZipCode { get; set; }
public List<Reference> LocationReferences { get; set; }
public string CountryCode { get; set; }
}
public class Reference {
public string LocationReference { get; set; }
}
public class PhoneInfo {
public PhoneNumberInfo PhoneNumber { get; set; }
}
public class PhoneNumberInfo {
public string PhoneType { get; set; }
public long PhoneNumber { get; set; }
}
}
答案 1 :(得分:0)
我只想从这里获得firstName和lastName字段。
对于此请求,您可以在项目中安装Newtonsoft.Json package,然后例如:
TextView tvfirst = FindViewById<TextView>(Resource.Id.firstname);
TextView tvlast = FindViewById<TextView>(Resource.Id.lastname);
Button btn = FindViewById<Button>(Resource.Id.btn);
btn.Click += (sender, e) =>
{
var jsonstring = @"{'consumerId':56704292158, 'categoryId':1, 'categoryDescription': 'Pessoa', 'firstName':'FN','lastName':'Last Name','fiscalDocuments':[{'fiscalDocument':{'documentType':'Brasil: nº CPF','cpf':199999992}}],'gender':'M','emailAddress':'r****@*.com','optIns':[{'optIn':{'brandName':'consul','acceptanceStatus':false}},{'optIn':{'brandName':'brastemp','acceptanceStatus':true}}],'communicationData':[{'communicationInfo':{'addressId':'lalala','phoneNumbers':[{'phoneNumber':{'phoneType':'mobilePhone','phoneNumber':5555555555}}],'streetAddress':'ANY STREET','streetNumber':123,'streetComplement':null,'streetDistrict':'ANY TOWN','cityName':'ANY CITY','stateCode':'XX','zipCode':'12345','locationReferences':[{'locationReference':'Mercado'}],'countryCode':'ZZ'}},{'communicationInfo':{'addressId':2.563244E+7,'phoneNumbers':[{'phoneNumber':{'phoneType':'mobilePhone','phoneNumber':5555555555}},{'phoneNumber':{'phoneType':'homePhone','phoneNumber':555555555}}],'streetAddress':'ANY STREET','streetNumber':123,'streetComplement':'CASA','streetDistrict':'ANY TOWN','cityName':'ANY CITY','stateCode':'XX','zipCode':'12345','locationReferences':[{'locationReference':'Ao lado do deposito lua nova'}],'countryCode':'ZZ'}}]}";
JToken token = JObject.Parse(jsonstring);
var firstname = token.SelectToken("firstName");
tvfirst.Text = firstname.ToString();
var lastname = token.SelectToken("lastName");
tvlast.Text = lastname.ToString();
};
我使用两个TextView
来显示名字和姓氏,并使用一个按钮来解析json字符串。
通过复制你的json文件,你的json文件中似乎有一个错误,节点为addressId
,你可以使用一些Json格式化程序来格式化你的json字符串,然后就可以看到问题了。我把它换成了#la; lalala&#34;在我的样本中进行测试。