我正在尝试创建一个带有多个ID的Web表单,并在MySql数据库中搜索该ID,然后在表中返回该行。
PHP脚本
<form method="post" name="display" action="multi.php" />
Enter the name you like to display the data from MySQL:<br>
<input type="text" name="name" multiple />
<input type="submit"/>
</form>
</html>
<?php
mysql_connect("localhost", "root", "root123") or die("Connection Failed");
mysql_select_db("myDB")or die("Connection Failed");
$name = array();
foreach ($_POST as $name)
{
$query = "SELECT * FROM check_12 where name = '$name'";
}
$result = mysql_query($query);
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo '<tr>
<td>'.$line['ID'].'</td>
<td>'.$line['Name'].'</td>
<td>'.$line['Email Id'].'</td>
<td>'.$line['Address'].'</td>
<td>'.$line['Phone number'].'</td>
<td>'.$line['Remark'].'</td>
</tr>';