有没有办法迭代多个数组并从每个数组返回不同的值？
例如：
["English League Championship: What will be the match result?", Aston Villa: Win or Draw","@ Fulham: Win",m57338o58525",m57338o58526]}
我希望同时迭代所有三个，但返回
[2017 Boston Marathon: Which COUNTRY will the MEN'S WINNER represent?","Kenya"," Any Other Country","m57336o58521",
"m57336o58522"]然后var json = require('./output.json');
var a = json.gameQuestion;
var b = json.info;
var c = json.propVal;
var res= [];
for(var i = 0; i < a.length; i++){
res.push([a[i],b[i*2+1],b[i*2+2],c[i*2],c[i*2+1]]);
}
console.log(res[0]);
console.log(res[1]);
console.log(res[2]);
console.log(res[3]);
console.log(res[4]);
console.log(res[5]);
和b我需要跳过第一个元素。
let ContactNumber: NSString = (phoneNumber.value).value(forKey:"digits") as! NSString
print(ContactNumber)
let localizedLabel = CNLabeledValue<NSString>.localizedString(forLabel: phoneNumber.label!)
print(localizedLabel)
我已经完成了第一次迭代，但是有时我会添加另一个for循环，它最终会返回j与第一个for循环的长度相同的次数。
更新：谢谢！这个问题解决了！
答案 0 :(得分：1)
如果我没错你，请查看
var a = [1,2,3]
var b = [69,4,5,6,7,8,9]
var c = [10,11,12,13,14,15]
var res= [];
for(var i = 0; i<a.length; i++){
res.push([a[i],b[i*2+1],b[i*2+2],c[i*2],c[i*2+1]]);
}
console.log(res[0]);
console.log(res[1]);
console.log(res[2]);
答案 1 :(得分：0)
你可以试试这个：
var a = [1,2,3]
var b = [69,4,5,6,7,8,9]
var c = [10,11,12,13,14,15]
//Since for each value in array a you need a different value in array b in a single iteration we will use different pointers for each array but value will be dependent on i
for(var i=0;i<a.length;i++){
var final = [];
j = 2*i+1; //j is the pointer that iterates over array 'b'
k = 2*i; //k iterates over array 'c'
final.push(a[i]);
final.push(b[j]);
final.push(b[j+1]);
final.push(c[k]);
final.push(c[k+1]);
console.log(final);
}