Question

步骤1.我需要根据索引合并3个数组。

步骤2.如果第一个数组中的两个项目匹配，我想合并它们的索引。

输入：

datesArray  = ["2017-04-20", "2017-04-27", "2017-04-20"]
timesArray  = ["13:00", "18:00", "14:00"]
pricesArray = ["40", "60", "50"]

输出：

[
  {
    "date": "2017-04-20",
    "times": [
      "13:00",
      "14:00"
    ],
    "prices": [
      "$40.00",
      "$50.00"
    ]
  },
  {
    "date": "2017-04-27",
    "times": [
      "13:00"
    ],
    "prices": [
      "$30.00"
    ]
  }
]

感谢您的帮助。

Answer 1

您可以使用key-value对对象进行分组，然后将其转换为数组。

var datesArray  = ["2017-04-20", "2017-04-27", "2017-04-20"]
var timesArray  = ["13:00", "18:00", "14:00"]
var pricesArray = ["40", "60", "50"]

var result = {}, mergedArray = []

for(var i=0;i<datesArray.length;i++){
  var e = datesArray[i]
  if(!result[e]){
      result[e]={ date: e, times: [], prices: [] }
  }
  result[e].times.push(timesArray[i])
  result[e].prices.push('$' + pricesArray[i] + '.00')
}

for (var key in result){
    if (result.hasOwnProperty(key)) {
         mergedArray.push(result[key]);
    }
}

console.log(mergedArray)

Answer 2

您可以使用forEach()循环执行此操作，并将一个空对象作为thisArg参数传递，您可以使用该参数按日期对元素进行分组。

＆＃13;

var datesArray  = ["2017-04-20", "2017-04-27", "2017-04-20"]
var timesArray  = ["13:00", "18:00", "14:00"]
var pricesArray = ["40", "60", "50"]

var result = [];
datesArray.forEach(function(e, i) {
  if(!this[e]) {
    this[e] = {date: e, times:[], prices: []}
    result.push(this[e]);
  }
  this[e].times.push(timesArray[i]);
  this[e].prices.push('$' + pricesArray[i] + '.00');
});

console.log(result);

＆＃13;

根据索引和重复索引将数组合并到新数组中

2 个答案: