Rextester

Question

我想用第一个元音分割一个字符串。如果下面的字母也是元音，那么它必须不会分裂，直到它到达序列中的最后一个元音。例如：

"Auxiliary" =＆gt; ["Au" "xiliary"]
"Doorknob" =＆gt; ["Doo" "rknob"]
"Green" =＆gt; ["Gree" "n"]

我做了：

"Auxiliary".split("u")
# => ["A", "uxiliary"]

比赛结束后我需要分手，而不是之前。我不确定我是否可以做"Auxiliary".split(/[aeiouAEIOU]/)之类的事情;这只会在第一次发现元音时分裂。

Answer 1

您可以尝试使用以下模式：

([^aeiou]*[aeiou]+)(.*)

([^aeiou]*[aeiou]+)    match and capture zero or more continuous non vowels
                       followed by one or more vowels
(.*)                   then capture the remainder of the string  

puts "Auxiliary".scan(/([^aeiou]*[aeiou]+)(.*)/i)
puts "Doorknob".scan(/([^aeiou]*[aeiou]+)(.*)/i)
puts "Green".scan(/([^aeiou]*[aeiou]+)(.*)/i)

<强>输出：

Au
xiliary
Doo
rknob
Gree
n

在这里演示：

Rextester

Answer 2

R = /
    \A        # match beginning of string
    [^aeiou]* # match zero or more non-vowels
    [aeiou]+  # match one or more vowels
    /ix       # case-indifferent and free-spacing regex definition modes

def split_after_vowels(str)
  return nil unless str =~ R
  i = Regexp.last_match.end(0)
  [str[0,i], str[i..-1]] 
end

split_after_vowels 'Aardvark'
  #=> ["Aa", "rdvark"] 
split_after_vowels 'taught'
  #=> ["tau", "ght"] 
split_after_vowels 'zzzzzz'
  #=> nil 
split_after_vowels 'zzzzzz sleep'
  #=> ["zzzzzz slee", "p"]

在匹配特定条件时拆分字符串

2 个答案:

Rextester