Question

对于版本4.10.4搜索的solr，我创建了文件synonyms.txt并应用synonymFilterFactory，如下所示：

<fieldType name="text_general" class="solr.TextField">  
     <analyzer>     
        <tokenizer class="solr.StandardTokenizerFactory"/>
        <filter class="solr.LowerCaseFilterFactory"/>
        <filter class="solr.WordDelimiterFilterFactory" generateWordParts="1" generateNumberParts="0" splitOnCaseChange="0" splitOnNumerics="0" catenateWords="1" catenateNumbers="0" catenateAll="0" preserveOriginal="1" stemEnglishPossessive="0"/>
     </analyzer>
     <analyzer type="query">
        <tokenizer class="solr.StandardTokenizerFactory"/>
        <filter class="solr.SynonymFilterFactory" synonyms="synonyms.txt" ignoreCase="true" expand="true"/>
        <filter class="solr.LowerCaseFilterFactory"/>
     </analyzer>
</fieldType>

synonyms.txt具有以下内容：

holland* => holland

holland, netherland, netherlands, niederlande

我在应用程序中有一些条件生成术语： holland*

在这种情况下，我希望显示的结果与我设置holland，netherland，netherlands，niederlande时的结果相同。

但目前，对于学期荷兰*，它没有给出匹配的结果。荷兰*的结果包含与术语“荷兰”相同的结果。或者＆＃39; netherland＆＃39;但那些是在底部，那么我们能否提升这些结果呢？

有没有人有任何想法，我怎么能实现呢？

以下是更多细节：

在荷兰的情况下，我得到一些结果，当我调试查询时，它显示为

"debug": {
    "rawquerystring": "holland",
    "querystring": "holland",
    "parsedquery": "(name:holland name:netherland name:netherlands name:niederlande)/no_coord",
    "parsedquery_toString": "name:holland name:netherland name:netherlands name:niederlande",
    "explain": {
      "country-NLD-de": "\n7.42217 = (MATCH) sum of:\n  7.42217 = (MATCH) weight(name:niederlande in 1775593) [DefaultSimilarity], result of:\n    7.42217 = score(doc=1775593,freq=1.0), product of:\n      0.5213204 = queryWeight, product of:\n        14.237252 = idf(docFreq=14, maxDocs=8413113)\n        0.036616646 = queryNorm\n      14.237252 = fieldWeight in 1775593, product of:\n        1.0 = tf(freq=1.0), with freq of:\n          1.0 = termFreq=1.0\n        14.237252 = idf(docFreq=14, maxDocs=8413113)\n        1.0 = fieldNorm(doc=1775593)\n",
      "country-NLD-en": "\n7.3550315 = (MATCH) sum of:\n  7.3550315 = (MATCH) weight(name:netherlands in 230095) [DefaultSimilarity], result of:\n    7.3550315 = score(doc=230095,freq=1.0), product of:\n      0.5189572 = queryWeight, product of:\n        14.172713 = idf(docFreq=15, maxDocs=8413113)\n        0.036616646 = queryNorm\n      14.172713 = fieldWeight in 230095, product of:\n        1.0 = tf(freq=1.0), with freq of:\n          1.0 = termFreq=1.0\n        14.172713 = idf(docFreq=15, maxDocs=8413113)\n        1.0 = fieldNorm(doc=230095)\n",
      "place-49218-de": "\n5.0385056 = (MATCH) sum of:\n  5.0385056 = (MATCH) weight(name:holland in 385574) [DefaultSimilarity], result of:\n    5.0385056 = score(doc=385574,freq=1.0), product of:\n      0.4295267 = queryWeight, product of:\n        11.730367 = idf(docFreq=183, maxDocs=8413113)\n        0.036616646 = queryNorm\n      11.730367 = fieldWeight in 385574, product of:\n        1.0 = tf(freq=1.0), with freq of:\n          1.0 = termFreq=1.0\n        11.730367 = idf(docFreq=183, maxDocs=8413113)\n        1.0 = fieldNorm(doc=385574)\n",

对于荷兰*，结果包含来自荷兰的一些记录，但调试部分如下：

"debug": {
    "rawquerystring": "holland*",
    "querystring": "holland*",
    "parsedquery": "name:holland*",
    "parsedquery_toString": "name:holland*",
    "explain": {
      "place-51432-de": "\n1.0 = (MATCH) ConstantScore(name:holland name:hollandarod name:hollande name:hollander name:hollanderei name:hollandia name:hollandischer name:hollands name:hollandsbjerg name:hollandsch name:hollandsche name:hollandscheveld name:hollandsdiep name:hollandskamp name:hollandske), product of:\n  1.0 = boost\n  1.0 = queryNorm\n",
      "place-49196-de": "\n1.0 = (MATCH) ConstantScore(name:holland name:hollandarod name:hollande name:hollander name:hollanderei name:hollandia name:hollandischer name:hollands name:hollandsbjerg name:hollandsch name:hollandsche name:hollandscheveld name:hollandsdiep name:hollandskamp name:hollandske), product of:\n  1.0 = boost\n  1.0 = queryNorm\n",
      "place-49207-de": "\n1.0 = (MATCH) ConstantScore(name:holland name:hollandarod name:hollande name:hollander name:hollanderei name:hollandia name:hollandischer name:hollands name:hollandsbjerg name:hollandsch name:hollandsche name:hollandscheveld name:hollandsdiep name:hollandskamp name:hollandske), product of:\n  1.0 = boost\n  1.0 = queryNorm\n",

在上面的dubug部分中，如果我们检查＆＃34; parsedquery＆＃34;部分，在荷兰和荷兰的情况下它是不同的*。所以我认为，特殊字符*不适用于SynonymFilterFactory。

Answer 1

据我所知，同义词文件不支持通配符。

在您的情况下，您可能还会遇到另一个问题，因为查询中的通配符通常用于搜索不完全匹配的结果。这取决于您的查询中使用的查询解析器。

换句话说，查询“holland*”搜索所有具有以“holland”开头的词条的文档。

如果您希望 Solr 将通配符视为一个简单的字符，您应该对其进行转义。

我看到的另一个错误，在您的字段定义中，您应该为两种情况（索引和查询）定义 analyzer 类型。

<块引用>

如果您为字段类型提供一个简单的定义，如上面的例子，那么它将用于索引和查询。

Answer 2

请尝试：

<fieldType name="text_general" class="solr.TextField" positionIncrementGap="100" multiValued="true">
  <analyzer type="index">
    <tokenizer class="solr.StandardTokenizerFactory"/>
    <filter class="solr.LowerCaseFilterFactory"/>
  </analyzer>
  <analyzer type="query">
    <tokenizer class="solr.StandardTokenizerFactory"/>
    <filter class="solr.SynonymGraphFilterFactory" synonyms="synonyms.txt" ignoreCase="true" expand="true" tokenizerFactory="solr.StandardTokenizerFactory"/>
    <filter class="solr.LowerCaseFilterFactory"/>
  </analyzer>
</fieldType>

synonym.txt文件中使用的特殊字符（例如*）在solr中不起作用

2 个答案: