Question

SELECT qurum_id, qurum, COUNT(qurum1) AS I FROM `qurum` AS qur
JOIN (SELECT id, qurum1,input_date FROM DATA ) `aa` ON qur.qurum_id = 
aa.qurum1
WHERE DATE_FORMAT(aa.input_date, '%Y') = $year AND DATE_FORMAT(aa.input_date, '%m') < 07

GROUP BY qurum_id
ORDER BY qurum_id

和

SELECT qurum_id, qurum, COUNT(qurum1) AS II FROM `qurum` AS qur2
JOIN (SELECT id, qurum1,input_date FROM DATA ) `bb` ON qur2.qurum_id = 
bb.qurum1
WHERE DATE_FORMAT(bb.input_date, '%Y') = $year AND DATE_FORMAT(bb.input_date, '%m') BETWEEN 06 AND 12

GROUP BY qurum_id
ORDER BY qurum_id

如何将这些查询加入1？我需要这样的列 - qurum_id，qurum，I，II。

Answer 1

您可以使用条件聚合。诀窍是根据月份条件采取条件计数记录，这对于您当前的两个查询是不同的。请注意，该年份的WHERE条件是不相关的，因为两个查询都共享此条件。

SELECT
    qurum_id,
    SUM(CASE WHEN DATE_FORMAT(aa.input_date, '%m') < 07
               THEN 1 END) AS I,
    SUM(CASE WHEN DATE_FORMAT(aa.input_date, '%m') BETWEEN 06 AND 12
               THEN 1 END) AS II
FROM qurum AS qur
INNER JOIN (SELECT id, qurum1,input_date FROM DATA ) AS aa
    ON qur.qurum_id = aa.qurum1
WHERE DATE_FORMAT(aa.input_date, '%Y') = $year
GROUP BY qurum_id
ORDER BY qurum_id

2使用2个不同的WHERE查询到1

1 个答案: