page.php
$sqlQuery = "";
$result = $mysqli->query($sqlQuery);
if (mysqli_affected_rows($mysqli) > 0) {
echo "success";
} else {
echo "error";
}
我想成功使用响应文本,但if条件不起作用。 我如何使用if。
感谢您的帮助。
$.ajax({
metod: "POST",
url: "page.php",
data: {data},
success: function (response) {
console.log(response); // It is working
notification("success"); // It is working
// response text is succes or error
if (response == 'success') {
btnLabel.html("DONE"); // It is not working
} else if (response == 'error') {
btnLabel.html("ERROR"); // It is not working
}
},
error: function (err) {
notification("error"); // It is working
}
});