我在postgresql上有这个查询：
COPY (SELECT
"UR_16PIX_Chih"."ID_UR",
"UR_16PIX_Chih"."IDEDOMUN15",
"UR_16PIX_Chih"."PIX1",
"UR_16PIX_Chih"."PIX2",
"UR_16PIX_Chih"."PIX3",
"UR_16PIX_Chih"."PIX4",
"UR_16PIX_Chih"."PIX5",
"UR_16PIX_Chih"."PIX6",
"UR_16PIX_Chih"."PIX7",
"UR_16PIX_Chih"."PIX8",
"UR_16PIX_Chih"."PIX9",
"UR_16PIX_Chih"."PIX10",
"UR_16PIX_Chih"."PIX11",
"UR_16PIX_Chih"."PIX12",
"UR_16PIX_Chih"."PIX13",
"UR_16PIX_Chih"."PIX14",
"UR_16PIX_Chih"."PIX15",
"UR_16PIX_Chih"."PIX16"
FROM
public."UR_16PIX_Chih"
WHERE
"UR_16PIX_Chih"."IDEDOMUN15" = '08061') TO
'/home/manager/data/Chihuahua/08061.csv' WITH CSV HEADER;
我想知道如何将'08061'替换为'08062'，接着替换'08063'，接下来替换为'08064'，接下来替换为'08065'等等......使用自动方式。同时我只是编辑查询用pgadmin sql编辑器中的下一个值替换'08061'值，但我需要一种自动执行此操作的方法。
答案 0 :(得分：0)
一个选项是create or replace function c()
returns void as $c$
declare r record;
begin
for r in
select distinct "IDEDOMUN15" as i
from public."UR_16PIX_Chih"
loop
execute format($$
copy (
select "ID_UR", ...
from public."UR_16PIX_Chih"
where "IDEDOMUN15" = '%1$s'
) to '/var/lib/pgsql/%1$s.csv'
$$, r.i);
end loop;
end;
$c$ language plpgsql;
功能：
a