Question

如何阻止其余的代码在NodeJs中执行（不是使用process.exit（）来定义应用程序只是说这是要执行的最后一行。

在普通的javascript中你有exit（），但这似乎不适用于nodejs。

以下是情况：

 connection.query(sql, [req.session.sessionUserPackagePassword] , function(err, rows, fields) {
   if (!err) {
     var userFound = false;
     for(var i=0; i< rows.length; i++) {
       // Make the comparaison case insensitive
       if ((rows[i].deliveredToUser).toLowerCase() == `no`) {
         userFound = true;
         console.log(userFound);
         [...]
     }
}
if (!userFound) {
  res.render('pickup/errorAlreadyDelivered', {});
  // exit here
}

console.log(userFound);

// If the query fails to execute
} else {
  console.log('Error while performing Query.');
  res.render('errorConnection', {});
}
});
connection.end();




  // Update the query to say the box has been delivered to user and specify time



 // Establish the connection
 [...]


    res.render('pickup/openPackageClose', {
          title: '',
          helpButtonURL: '/help/help-dropPackage',
          helpButtonTitle: 'Help'


      });



    });

基本上当满足这个条件时，我希望其余的代码不被执行

if (!userFound) {
        res.render('pickup/errorAlreadyDelivered', {});
        // exit here 
}

Answer 1

connection.end();然后return;似乎可能适合您。

Answer 2

因此，基于您对我的其他答案的评论，听起来您的程序结构并非我认为的那样。这应该有效：

connection.query(sql, [req.session.sessionUserPackagePassword] , function(err, rows, fields) {
   if (!err) {
     var userFound = false;
     for(var i=0; i< rows.length; i++) {
       // Make the comparaison case insensitive
       if ((rows[i].deliveredToUser).toLowerCase() == `no`) {
         userFound = true;
         console.log(userFound);
         [...]
     }
}

if (!userFound) {
  res.render('pickup/errorAlreadyDelivered', {});
  connection.end();
} else { 
  console.log(userFound);
  console.log('Error while performing Query.');
  res.render('errorConnection', {});
  connection.end();
}

如何阻止其余代码执行NodeJ？

2 个答案: