Question

您正在制作一个允许用户互相关注的脚本，但是action.php文件来完成这项工作让我很头疼或者我不知道哪里出错了我有3个功能 -check_count检查用户是否已经关注了另一个用户 -follow_user执行跟随用户查询 -unfollow_user执行取消关注用户查询

然后，我有动作php文件从后续和取消关注链接获取ID

//home page
<div class="panel panel-default">
<div class="panel-body">
<?php
$users = show_users();
$following = following($_SESSION['login']);
if (count($users)){
foreach ($users as $key => $value){
echo $key," ", $value;
if(in_array($key, $following)){
echo " <small><a href='action.php?id=$key&do=unfollow'>unfollow</a>  </small>","<br>";
}else{
echo " <small><a href='action.php?id=$key&do=follow'>follow</a> </small>","<br>";
                                    }
                                }
                            }else{
                               echo "<p>","<b>","There are no users in the system","<b>","<p>"; 
                            }
                            ?>


                            </div>
                        </div>
//action .php file
<?php

在session_start（）; //会话变量在这里下载

include_once（＆＃39;包括/ dbconnect.php＆＃39）; include_once（＆＃39;的functions.php＆＃39）;

$ id = $ _GET [＆＃39; id＆＃39;]; $ do = $ _GET [＆＃39; do＆＃39;];

开关（$ do）{ 案例＆＃34;关注＆＃34;： follow_user（$ _ SESSION [＆＃39;登录＆＃39;]，$ ID）; $ msg =＆＃34;您关注了用户！＆＃34 ;; 打破;

case "unfollow":
    unfollow_user($_SESSION['login'],$id);
    $msg = "You have unfollowed a user!";
break;

} $ _SESSION [＆＃39; message＆＃39;] = $ msg;

头（＆＃34;位置：home.php＆＃34）; ？＆GT;

 //the functions
 function check_count($first,$second){
    global $conn;
    $sql="SELECT COUNT(*) FROM following WHERE fuser_id='$second' AND follower_id='$first'";
    $result=mysqli_query($conn,$sql);
    $row = mysql_fetch_row($result);
    return $row[0];
}

function follow_user($me,$them){
    global $conn,$id;
    $count = check_count($me,$them);
        if($count==0){
            $sql="INSERT INTO following (fuser_id,follower_id) VALUES($them,$me)";
            $result=mysqli_query($conn,$sql);
        }

}

function unfollow_user($me,$them){
    global $conn,$id;
    $count = check_count($me,$them);
        if($count !=0){
            $sql="DELETE FROM following WHERE fuser_id='$them' and follower_id='$me' limit 1";
            $result=mysqli_query($conn,$sql);
        }

}

功能错误跟随/取消关注用户

0 个答案: