我有一个调用pthread_join
的循环,但循环的顺序与线程终止的顺序不匹配。
如何监控线程完成然后调用join?
for ( int th=0; th<sections; th++ )
{
cout<<"start joining "<<th<<endl<<flush;
result_code = pthread_join( threads[th] , (void**)&status);
cout<<th<<" join error "<<strerror(result_code)<<endl<<flush;
cout<<"Join status is "<<status<<endl<<flush;
}
这是我的解决方案,它似乎通过提供第一个来最大化多线程吞吐量 完成线程。此解决方案不依赖于pthread_join循环顺序。
// loop & wait for the first done thread
std::bitset<Nsections> ready;
std::bitset<Nsections> done;
ready.reset();
for (unsigned b=0; b<sections; b++) ready.flip(b);
done = ready;
unsigned currIdx = 1;
int th = 0;
int th_= 0;
int stat;
while ( done.any() )
{
// main loops waiting for 1st thread to complete.
// completion is checked by global vector
// vStatus (singlton write protected)
// and not by pthread_exit returned value,
// in ordder to maximize throughput by
// post processig the first
// finished thread.
if ( (obj.vStatus).empty() ) { Sleep (5); continue; }
while ( ready.any() )
{
if ( sections == 1 ) break;
if ( !(obj.vStatus).empty() )
{
if ( currIdx <= (obj.vStatus).size() )
{
th_ = currIdx-1;
std::string s =
ready.to_string<char,std::string::traits_type,std::string::allocator_type>();
cout<<"checking "<<th_<<"\t"<<s<<"\t"
<<(ready.test(th_)?"T":"F")<<"\t"<<(obj.vStatus)[th_].retVal <<endl;
if ((obj.vStatus)[th_].retVal < 1)
{
if (ready.test(th_))
{
th=th_;
ready.reset(th);
goto retry;
}
}
}
}
Sleep (2);
} // while ready
retry:
cout<<"start joining "<<th<<endl<<flush;
result_code = pthread_join( threads[th] , (void**)&status);
switch (result_code)
{
case EDEADLK: goto retry; break;
case EINVAL:
case ESRCH:
case 0:
currIdx++;
stat = status->retVal;
free (status);
done.reset(th);
std::string s =
done.to_string<char,std::string::traits_type,std::string::allocator_type>();
cout<<"joined thread "<<th<<"\t"<<s<<"\t"
<<(done.test(th)?"T":"F")<<"\t"<<stat <<endl;
while (true)
{
auto ret=pthread_cancel ( threads[th] ) ;
if (ret == ESRCH) { netTH--; break; }
Sleep (20);
}
break;
}
答案 0 :(得分:0)
如何监控线程完成然后调用join?
让联接检测完成。 (即什么都不做特别)
我有一个调用pthread_join的循环,但是循环的顺序与线程终止的顺序不匹配。
循环的顺序无关紧要。
a)thread[main]
调用thread[1].'join'
只会暂停,直到thread[1]
退出。之后,将允许线程[main]继续循环的其余部分。
b)当thread[2]
在thread[1]
之前终止时,调用thread[main]
的{{1}}只会立即返回。再次,thread[2].join
继续。
c)确保thread[main]
在thread[1]
之前终止(以匹配循环序列)的努力是一项令人惊讶的耗时工作,没有任何好处。
正在更新...正在寻找我认为已提交的代码。