MYSQL查询:
SELECT * FROM `pet_info` LEFT JOIN `lostpets` ON `pet_info`.`id` = `lostpets`.`petid` LEFT JOIN `pet_images` ON `pet_info`.`id` = `pet_images`.`petid` LEFT JOIN ON `pet_info`.`pet_cat` CASE WHEN `pet_info`.`pet_cat` = 1 THEN `dog_breeds`.`id` WHEN `pet_info`.`pet_cat` = 2 THEN `cat_breeds`.`id` END WHERE `pet_info`.`pet_user_id` = 581
错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ON `pet_info`.`pet_cat` CASE WHEN `pet_info`.`pet_cat` = 1 THEN `do' at line 7
为什么出现错误请帮助我。我可以解决这个错误吗?
答案 0 :(得分:0)
以下是查询的格式化版本,突出显示了一些错误。
SELECT *
FROM pet_info p
LEFT
JOIN lostpets l
ON p.id = l.petid
LEFT
JOIN pet_images i
ON p.id = i.petid
LEFT
JOIN !! ERROR 1
ON p.pet_cat !! ERROR 2
CASE WHEN p.pet_cat = 1
THEN d.id !! ERROR 3
WHEN p.pet_cat = 2
THEN c.id END !! ERROR 4
WHERE p.pet_user_id = 581