Question

运行此代码时出现意外$ dbConn错误，但我确实编写了$ dbConn的代码，我不知道为什么......

这里是我的user.php，包含登录数据库和用户表。

<?php

define('DB_NAME','login');
define('DB_SERVER','localhost');
define('DB_USERNAME','root');
define('DB_PASSWORD','');

class User{
  $dbConn = new PDO("mysql:host=".DB_SERVER.";dbname=".DB_NAME,DB_USERNAME,DB_PASSWORD);
  $dbConn->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION);


  public function Login($name, $password){
    if(!empty($name) && !empty($password)){
      $statement = $dbConn->prepare("select * from users where name=? and password=?");
      $statement->bindParam(1, $name);
      $statement->bindParam(2, $password);
      $statement->execute();

      if($statement->rowCount() == 1){
        echo "User verified, Access granted.";
      }else{
        echo "Incorrect username or password";
      }
    }else{
      echo "Please enter username and password";
    }

  }


}


 ?>

以下是index.php

<?php

include_once('user.php');

if(isset($_POST['submit'])){
  $name     = $_POST['user'];
  $password = $_POST['password'];

  $object = new User();
  $object->Login($name, $password);
}


 ?>

<html>
<head>
</head>
<body>
  <form method="post" action="index.php">
    Username: <input type="text" name="user">
    Password: <input type="text" name="password">
    <input type="submit" name="submit" value="Login">
  </form>
</body>
</html>

任何人都可以帮我解决我的问题吗？非常感谢和赞赏。

Answer 1

您不能在类之类的方法之外拥有可执行代码：

class User
{

  $dbConn = new PDO(...);
  $dbConn->setAttribute(...);

  public function Login($name, $password){
  }

}

如果要初始化某些内容，可以使用构造函数：

class User
{

  protected $dbConn;

  public function __construct()
  {
      $this->dbConn = new PDO(...);
      $this->dbConn->setAttribute(...);
  }

}

解析错误：语法错误，意外＆＃39; $ dbConn＆＃39;

1 个答案: