Question

我有三张桌子：

表：用户/ 列： user_id，电子邮件，用户名
表格：activities / 列：对象，类型，like_count
表格：activities2 / 列：对象，target_type，主题，类型

活动表中的like_count没有问题，我用这个查询计算了所有这些：

SELECT SUM(activities.like_count) AS likes, users.user_id, users.email, users.username
FROM activities
INNER JOIN users
ON activities.subject = users.user_id
GROUP BY user_id

但是，每当其他类型的帖子都被喜欢时，活动表中还有另一个计数被插入（未更新），我通过此查询计算它们：

SELECT activities.subject, activities.object, COUNT(activities.type) AS likes
FROM activities
INNER JOIN activities2
ON activities.object = activities2.object AND activities2.target_type = 'parent'
WHERE activities2.type LIKE 'like_%'
GROUP BY activities2.subject

但是当我想要将它们连接在一起时，问题就从这里开始了！我想计算like_count +插入该表（activities2）中的喜欢的数量，其中包含＆＃39;像_＆＃39;除此之外，我想加入与其他表（用户）中的user_id相关的主题（在活动表中）。

我的最后一个问题是：

SELECT users.user_id, users.email, users.username, activities.object, COUNT(activities.type)+SUM(activities.like_count) AS likes
FROM activities
INNER JOIN activities2
ON activities.object = activities2.object AND activities2.target_type = 'parent'
INNER JOIN users
ON activities.subject = users.user_id
WHERE activities2.type LIKE 'like_%'
GROUP BY users.user_id

问题是加入时，它获取的用户信息不是我想要的信息。总之，我想要这样的事情：

user_id------email-----------------username----------object-------likes
2521---------a@b.com---------------abc---------------9578---------3
5484---------c@d.com---------------def---------------8547---------16
8431---------e@f.com---------------ghi---------------4584---------1

并且当然结果是这样，但只有喜欢是正确的但是用户表中的user_id，email，username的列不是！

我想知道你是否愿意帮忙修复它。我真的厌倦了尝试并面对没有结果:(

用户表数据：

user_id-------------email---------------username
1-------------------a@b.com-------------abc
2-------------------c@d.com-------------def
3-------------------e@f.com-------------ghi

活动表数据：

object----------type----------------like_count------subject
20--------------like_video----------0---------------1
20--------------like_photo----------0---------------2
33--------------like_music----------0---------------3
33--------------some_other_type-----5---------------6
33--------------some_other_type-----8---------------10

活动2表数据：

object------target_type-----subject-----type
20----------parent----------30----------like_video
21----------owner-----------40----------like_audio
22----------parent----------50----------something_not_start_with_like_

我想：

user_id------email-----------------username----------object-------likes
1------------a@b.com---------------abc---------------9578---------(sum of like_count + count of type which has like_ in first characters)
2------------c@d.com---------------def---------------8547---------(sum of like_count + count of type which has like_ in first characters)
3------------e@f.com---------------ghi---------------4584---------(sum of like_count + count of type which has like_ in first characters)

Answer 1

考虑使用派生表加入聚合查询，然后在外部查询中运行添加计算。此外， object 列下方已从第二个聚合查询的GROUP BY子句中删除，但仍在JOIN中使用，因为您需要在主题级别进行求和。

SELECT u.user_id, u.email, u.username, a.`object`, u.likes + a.likes as `total_likes`
FROM
   (SELECT SUM(activities.like_count) AS likes, users.user_id, users.email, users.username
    FROM activities
    INNER JOIN users
    ON activities.subject = users.user_id
    GROUP BY user_id, users.email, users.username) u

INNER JOIN
   (SELECT activities.subject, COUNT(activities.type) AS  likes
    FROM activities
    INNER JOIN activities2
    ON activities.object = activities2.object AND activities2.target_type = 'parent'
    WHERE activities2.type LIKE 'like_%'
    GROUP BY activities2.subject) As a

ON u.user_id = a.subject

统计和汇总三个表并获得用户信息

1 个答案: