Question

你能帮我用trim修剪它的结果

(0, None, 1492333402, (b'sendgrid.net',))
(0, None, 1492331992, (b'internal-prolb-1409411760.eu-west-1.elb.amazonaws.com',))
(0, None, 1492333397, (b'edge.ssl.deals.souq.com',))

这种格式。

sendgrid.net
internal-prolb-1409411760.eu-west-1.elb.amazonaws.com
edge.ssl.deals.souq.com

下面是我的代码

#!/usr/bin/python
import sys
import socket
import adns
import time
from dns import resolver,reversename

results = []
hostlist = sys.argv[1]
hostarray = []

s=adns.init()
with open(hostlist, 'r') as f:
    for hostname in f:
        if hostname.split(':'):
            hostarray.append(hostname.split(':')[0])
        else:
            hostarray.append(hostname)

for hostname in hostarray:
    try:
        ip = socket.gethostbyname(hostname.strip())
    except socket.gaierror:
        try:
            ip = socket.gethostbyname('.'.join(hostname.strip().split('.')[1:]))
        except socket.gaierror as e:
            continue    
        except socket.error as e:
            continue
    results.append((ip, hostname.strip()))
def main():
    for (ip, hostname) in sorted(results, key=lambda item: socket.inet_aton(item[0])):
        x = (s.synchronous(hostname,adns.rr.CNAME))
        print (x)
main()

我的循环结束后，我得到的结果如下。请帮忙整理一下，谢谢

Answer 1

directionsDisplay = new google.maps.DirectionsRenderer({
    draggable: true
});

Answer 2

您想要访问元组中元组中的字符串。可以使用与列表相同的方式访问元组。

tuple[3][0]

可以使用

解码字符串

string.decode()

如何根据结果修剪特定关键字

2 个答案: