Question

大家好，我可以帮助我完成我的项目，我在计算两个日期之间的渲染时间时遇到问题。具体来说，我的问题是在晚上10点到早上6点之间计算员工的夜间差异

e.g1: If the employee time in is 2017-01-01 21:00 (9pm) and the time out is 2017-01-02 05:00 (5am) the output will be: 7hours. 

e.g.2: time in = 2017-01-01 17:00 (5pm) and time out = 2017-01-02 02:00 (2am) the output will be: 4 hours.

e.g.3: timein = 2017-01-01 02:00 (2am) and time out = 2017-01-01 10:00 (10am) the output will be: 4 hours.

如果日志在晚上10点到早上6点之间通过，则计数将开始

请提前帮助你。

Answer 1

下面：

<?php
$output = abs((strtotime("2017-01-01 21:00") - strtotime("2017-01-02 05:00")) / 3600);
echo $output; // Outputs 8

Answer 2

您可以使用unix时间：

$Date1 = strtotime(date("2017-01-01 17:00"));
$Date2 = strtotime(date("2017-01-02 02:00"));
$hours = ($Date2 - $Date1) / 3600;

Answer 3

您可以使用DateTime函数：

int length(const int& value) noexcept {
    //if (std::is_integral<int>::value) { this branch is taken
        return value;
    //else                           discarded
    //    return value.length();     discarded
}

std::size_t length(const std::string& value) noexcept {
    //if (std::is_integral<int>::value) { discarded
    //    return value;                   discarded
    //else                           this branch is taken
        return value.length();
}

输出：

<?php
$date1 = new DateTime("2017-01-01 21:00");
$date2 = new DateTime("2017-01-02 05:00");
if (($date1->format('H') >= 22) && (($date2->format('H') <= 6))) {
    $interval = $datetime1->diff($datetime2);
    echo $interval->format('%R%h hours');
} else {
    echo "0 hours";
}

文档：http://php.net/manual/en/datetime.diff.php和http://php.net/manual/en/datetime.format.php

Answer 4

到目前为止，这是我的工作

function computeNightDifferential($time_in, $time_out)
{
    $start = "2016-01-01 22:00:00"; // 10pm
    $end = "2016-01-02 06:00:00"; // 6am

    $time_in = "2016-01-01 23:00:00";
    $time_out = "2016-01-02 06:30:00";
    $night_diff = 0;
    if($time_out > $start AND $time_out <= $end AND $time_in <= $start){
        $night_diff = abs(strtotime($start) - strtotime($time_out)) / 3600;
    }else if($time_out <= $end AND $time_in > $start){
        $night_diff = abs(strtotime($time_in) - strtotime($time_out)) / 3600;
    }else if($time_out > $end AND $time_in > $start){
        $night_diff = abs(strtotime($time_in) - strtotime($end)) / 3600;
    }else if($time_out > $end AND $time_in <= $start){
        $night_diff = abs(strtotime($start) - strtotime($end)) / 3600;
    }
    echo $night_diff;
}

感谢您的帮助！

PHP - 计算两个日期时间之间的时间

4 个答案: