打开processsing.exe时如何更改Launcher args?我正在运行64位Windows系统,我需要能够以32位模式运行JVM。
CmdLine: C:\dev\libs\processing-1.2.1\processing.exe --l4j-debug
WOW64: yes
Working dir: C:\dev\libs\processing-1.2.1\.
Bundled JRE: java
Check launcher: C:\dev\libs\processing-1.2.1\java\bin\javaw.exe (n/a)
64-bit search: SOFTWARE\JavaSoft\Java Development Kit...
Match: SOFTWARE\JavaSoft\Java Development Kit\1.6
Match: SOFTWARE\JavaSoft\Java Development Kit\1.6.0_21
Match: SOFTWARE\JavaSoft\Java Development Kit\1.6.0_22
Using 64-bit runtime.
Check launcher: C:\Program Files\Java\jdk1.6.0_22\bin\javaw.exe (OK)
Add classpath: lib\pde.jar
Add classpath: lib\core.jar
Add classpath: lib\jna.jar
Add classpath: lib\ecj.jar
Add classpath: lib\antlr.jar
Add classpath: lib\ant.jar
Add classpath: lib\ant-launcher.jar
Launcher: C:\Program Files\Java\jdk1.6.0_22\bin\javaw.exe
Launcher args: -Xms128m -Xmx128m -classpath "lib;C:\Program Files\Java\jdk1.6.0_22\lib\tools.jar;lib\pde.jar;lib\core.jar;lib\jna.jar;lib\ecj.jar;lib\antlr.jar;lib\ant.jar;lib\ant-launcher.jar" processing.app.Base
Args length: 198/32768 chars
Exit code: 259
答案 0 :(得分:-1)
grep -iR "ant-launcher.jar" *
程序文件夹(C:\ dev \ libs \ processing-1.2.1)中的应该足以找出这些参数的位置。 Windows没有grep?得到它here。