Question

在我的情况下，如果用户是列表视图中该团队的团队成员，当他长按团队时，会出现一个对话框。但是，如果他不是，那么什么都不会发生。我设法在用户创建团队后显示对话框，但是当我注销并使用相同的帐户登录时，即使我是teamOwner，当我长按它时对话框也不会出现。我将用户的电子邮件存储为teamOwner。我的代码如下所示，如果您需要更多信息，请与我们联系。

MainActivity：

listViewTeams.setOnItemLongClickListener(new AdapterView.OnItemLongClickListener() {
        FirebaseUser user = firebaseAuth.getCurrentUser();
        @Override
        public boolean onItemLongClick(AdapterView<?> adapterView, View view, int i, long l) {
            Team team = teams.get(i);
            String owner = user.getEmail();

            if (owner == team.getTeamOwner()) {
                showUpdateDeleteDialog(team.getTeamId(), team.getTeamName());
            }
            else{

            }
            return true;
        }
    });

AddActitvity：

private void addTeam() {
    //getting the values to save
    String name = editTextName.getText().toString().trim();
    String sport = spinnerSport.getSelectedItem().toString();
    String date = textDate.getText().toString();
    String time = textTime.getText().toString();

    FirebaseUser user = firebaseAuth.getCurrentUser();
    user.getEmail();

    //checking if the value is provided
    if (!TextUtils.isEmpty(name)) {

        //getting a unique id using push().getKey() method
        //it will create a unique id and we will use it as the Primary Key for our Team
        String id = databaseTeams.push().getKey();
        String owner = user.getEmail();
        String member = user.getEmail();

        //creating an Team Object
        Team team = new Team(id, name, sport, owner, date, time);
        Member members = new Member(member);

        //Saving the Team
        databaseTeams.child(name).setValue(team);
        databaseMembers.child(name).setValue(members);

        //setting edittext to blank again
        editTextName.setText("");

        //displaying a success toast
        Toast.makeText(this, "Team added", Toast.LENGTH_LONG).show();
    } else {
        //if the value is not given displaying a toast
        Toast.makeText(this, "Please enter a name", Toast.LENGTH_LONG).show();
    }
}

Team.java

public class Team {
private String teamId;
private String teamName;
private String teamSport;
private String teamOwner;
private String date;
private String time;

public Team() {

}

public Team(String teamId, String teamName, String teamSport, String teamOwner, String date, String time) {
    this.teamId = teamId;
    this.teamName = teamName;
    this.teamSport = teamSport;
    this.teamOwner = teamOwner;
    this.date = date;
    this.time = time;
}

public String getTeamId() {return teamId;}

public  String getTeamName() {
    return teamName;
}

public String getTeamSport() {
    return teamSport;
}

public String getTeamOwner() { return  teamOwner; }

public String getDate(){ return date; }

public String getTime() { return time; }

}

数据库：

Answer 1

好的我觉得我找到了问题的解决方案。在我的主要活动中，我使用'=='而不是.equals（），这是不推荐的。

参考这里： How do I compare strings in Java?

重新登录后，Firebase对话框不会出现

1 个答案: