使用jquery ajax

Question

我想使用ajax.ajax成功运行函数警告run.but数据将数据插入名为vacancy的mysql表中。但数据不保存在table.and错误是occer.i我是php和ajax的新手

html代码

    <form class="form-horizontal" action="postvaccode2.php" type="post">
         <fieldset>

             <!-- Form Name -->
             <legend>Post Vacancy</legend>

             <!-- Select Basic -->
             <div class="form-group">

                 <div class="col-md-5">
                     <select id="cato" name="cato" class="form-control" id="cato">
                         <option value="IR">IT</option>
                         <option value="USA">Finance</option>
                     </select>
                 </div>
             </div>

             <!-- Text input-->
             <div class="form-group">

                 <div class="col-md-6">
                     <input id="comid" name="comid" type="text" placeholder="comid" class="form-control input-md" required="" >

                 </div>
             </div>

             <!-- Text input-->
             <div class="form-group">

                 <div class="col-md-6">
                     <input id="loc" name="loc" type="text" placeholder="city or town" class="form-control input-md" required="">

                 </div>
             </div>

             <!-- Text input-->
             <div class="form-group">

                 <div class="col-md-8">
                     <input id="qul" name="qul" type="text" placeholder="qulification" class="form-control input-md">

                 </div>
             </div>

             <!-- Text input-->
             <div class="form-group">

                 <div class="col-md-8">
                     <input id="indate" name="indate" type="date" placeholder="indate" class="form-control input-md">

                 </div>
             </div>

             <!-- Text input-->
             <div class="form-group">

                 <div class="col-md-4">
                     <input id="expdate" name="expdate" type="date" placeholder="expdate" class="form-control input-md" required="">

                 </div>
             </div>

             <div class="form-group">

                 <div class="col-md-8">
                     <input id="gpa" name="gpa" type="text" placeholder="gpa" class="form-control input-md">

                 </div>
             </div>

             <div class="form-group">

                 <div class="col-md-8">
                     <input id="des" name="des" type="text" placeholder="description" class="form-control input-md">

                 </div>
             </div>

             <div class="form-group">

                 <div class="col-md-8">
                     <input id="title" name="title" type="text" placeholder="title" class="form-control input-md">

                 </div>
             </div>

             <div class="form-group">

                 <div class="col-md-8">
                     <input id="comname" name="comname" type="text" placeholder="name" class="form-control input-md">

                 </div>
             </div>

             <div class="form-group">

                 <div class="col-md-8">
                     <input id="vacpost" name="vacpost" type="submit" class="form-control input-md">

                 </div>
             </div>

         </fieldset>
     </form>

脚本

    </script>

     <script>
         $('#vacpost').click(function () {
             $.ajax({
                 type: "POST",
                 url: "postvaccode2.php",
                 data:{id:$('#comid').val(),cato:$('#cato').val(),loc:$('#loc').val(),quli:$('#qul').val(),indate:$('#indate').val(),expdate:$('#expdate').val(),gpa:$('#gpa').val(),des:$('#des').val(),title:$('#title').val(),comname:$('#comname').val()},

                 success:function () {
                     alert('Sccessfuly Post the Job vacency');
                     location.reload(true);
                 }

             });
         });
     </script>

postvaccode2.php

    <?php
    $conn=mysqli_connect("localhost","root","","internship");

    if (mysqli_connect_errno()) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

    $id=$_POST['id'];
    $cato=$_POST['cato'];
    $loc=$_POST['loc'];
    $quli=$_POST['quli'];
    $indate=$_POST['indate'];
    $expdate=$_POST['expdate'];
    $gpa=$_POST['gpa'];
    $des=$_POST['des'];
    $title=$_POST['title'];
    $comname=$_POST['comname'];

    $sql="insert into vacancy(companyid,catogary,location,qulification,indate,expectgpa,description,title,expdate,companyname) values('$id','$cato','$loc','$quli','$indate','$gpa','$des','$title','$expdate','$comname',)";
    $conn->query($sql);
     ?>