应用程序应该在数据库中添加一个新行，但它会停止工作

Question

有人可以告诉我这段代码有什么问题吗？它应该在数据库中添加一个新行，但是当我运行它时，应用程序会停止。我检查了联系人的详细信息，但是当在数据库中添加新信息时，它就会停止工作。

public class MyDBHandler extends SQLiteOpenHelper {

private static final int DATABASE_VERSION = 1;
private static final String DATABASE_NAME = "ContactsDetails.db";
public static final String TABLE_NAME = "ConactsDetails";
public static final String COLUMN_ID = "_id";
public static final String COLUMN_FIRST_NAME = "first_name";
public static final String COLUMN_SURNAME = "surname";
public static final String COLUMN_DESCRIPTION = "description";
public static final String COLUMN_PHONE = "phone";
public static final String COLUMN_EMAIL = "email";
public static final String COLUMN_USERNAME = "username";
public static final String COLUMN_PASSWORD = "password";

public MyDBHandler(Context context, String name, SQLiteDatabase.CursorFactory factory, int version){
    super(context, DATABASE_NAME, factory, version);
}

@Override
public void onCreate(SQLiteDatabase db) {
    String query = "CREATE TABLE " + TABLE_NAME + "(" +
            COLUMN_ID + " INTEGER PRIMARY KEY AUTOINCREMENT" +
            COLUMN_FIRST_NAME + " TEXT " +
            COLUMN_SURNAME + " TEXT " +
            COLUMN_DESCRIPTION + " TEXT " +
            COLUMN_PHONE + " TEXT " +
            COLUMN_EMAIL + " TEXT " +
            COLUMN_USERNAME + " TEXT " +
            COLUMN_PASSWORD + " TEXT " +
            ");";
    db.execSQL(query);
}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
    onCreate(db);
}

//add new contact's details
public void addContact(NewUserContacts contact){
    ContentValues values = new ContentValues();
    values.put(COLUMN_FIRST_NAME, contact.getFirstName());
    values.put(COLUMN_SURNAME, contact.getSurname());
    values.put(COLUMN_DESCRIPTION, contact.getDescription());
    values.put(COLUMN_PHONE, contact.getPhone());
    values.put(COLUMN_EMAIL, contact.getEmail());
    values.put(COLUMN_USERNAME, contact.getUsername());
    values.put(COLUMN_PASSWORD, contact.getPassword());

    SQLiteDatabase db = getWritableDatabase();
    db.insert(TABLE_NAME, null, values);
    db.close();
}
}