Question

我遇到的问题是随机生成的数字结果与用户输入不匹配，如果用户猜错了，它只输出第一个语句而不是掉到else。

#include <iostream>
#include <ctime>
#include <cstdlib>
#include <string>

using namespace std;


int main()
{

    int bank = 10;
    int heads = 0;
    int tails = 1;
    char response;
    string headsTails;
    int coinToss = rand() % 2;
    srand(static_cast<int>(time(0)));


    cout << "Welcome to the coin flip game. It cost a dollar to play. " <<  endl;
    cout << "If you guess correctly you will win $2.00 dollars " << endl;
    cout << "Do you want to play? (Y/N) " << endl;
    cin >> response;


    while (toupper(response) == 'Y')
    {
        cout << "Your bank is $" << bank << " dollars." << endl;
        cout << "Enter head or tails (H/T)" << endl;
        cin >> response;

        coinToss = rand() % 2;
        headsTails = coinToss ? "Heads" : "Tails";

        if (coinToss == heads || coinToss == tails)
        {
            cout << "Winner! The coin flip came up " << headsTails << endl;
            cout << "Would you like to play again? (Y/N) " << endl;
            cin >> response;
            bank += 2;
        }
        else
        {
            cout << "Sorry, you lose. The coin flip came up " << headsTails << 
endl;
            cout << "Would you like to play again? (Y/N) " << endl;
            cin >> response;
            bank -= 1;
        }

    }
    cout << "Thanks for playing! Your bank is " << bank << endl;
    cout << "Please come again! " << endl;
    return 0;
}

Answer 1

if (coinToss == heads || coinToss == tails)

这种情况是错误的，因为你自己将coinToss设置为0或1，它总是会评估为真。

您必须使用您向用户提出的response变量，例如：

int guess = response == 'T' ? 1 : 0; // convert the user input to the same values used throughout the program.
if(guess == coinToss)
//won..
else
//lost..

随机生成的数字结果与用户输入不匹配

1 个答案: