Question

此资源定义很好：

Route::resource('servers', 'ServerController');

给出：

+--------+-----------+-----------------------+-----------------+-----------------------------------------------+--------------+
| Domain | Method    | URI                   | Name            | Action                                        | Middleware   |
+--------+-----------+-----------------------+-----------------+-----------------------------------------------+--------------+
|        | GET|HEAD  | servers               | servers.index   | App\Http\Controllers\ServerController@index   | web          |
|        | POST      | servers               | servers.store   | App\Http\Controllers\ServerController@store   | web          |
|        | GET|HEAD  | servers/create        | servers.create  | App\Http\Controllers\ServerController@create  | web          |
|        | GET|HEAD  | servers/{server}      | servers.show    | App\Http\Controllers\ServerController@show    | web          |
|        | PUT|PATCH | servers/{server}      | servers.update  | App\Http\Controllers\ServerController@update  | web          |
|        | DELETE    | servers/{server}      | servers.destroy | App\Http\Controllers\ServerController@destroy | web          |
|        | GET|HEAD  | servers/{server}/edit | servers.edit    | App\Http\Controllers\ServerController@edit    | web          |
+--------+-----------+-----------------------+-----------------+-----------------------------------------------+--------------+

但是我需要将它包装成一个前缀如下的组：

Route::group(['prefix' => 'servers'], function()
{
    Route::resource('/', 'ServerController', ['names' => 'servers']);
});

问题就出现了，因为前缀参数化路由的参数是空的：

+--------+-----------+-----------------+-----------------+-----------------------------------------------+--------------+
| Domain | Method    | URI             | Name            | Action                                        | Middleware   |
+--------+-----------+-----------------+-----------------+-----------------------------------------------+--------------+
|        | GET|HEAD  | servers         | servers.index   | App\Http\Controllers\ServerController@index   | web          |
|        | POST      | servers         | servers.store   | App\Http\Controllers\ServerController@store   | web          |
|        | GET|HEAD  | servers/create  | servers.create  | App\Http\Controllers\ServerController@create  | web          |
|        | GET|HEAD  | servers/{}      | servers.show    | App\Http\Controllers\ServerController@show    | web          |
|        | PUT|PATCH | servers/{}      | servers.update  | App\Http\Controllers\ServerController@update  | web          |
|        | DELETE    | servers/{}      | servers.destroy | App\Http\Controllers\ServerController@destroy | web          |
|        | GET|HEAD  | servers/{}/edit | servers.edit    | App\Http\Controllers\ServerController@edit    | web          |
+--------+-----------+-----------------+-----------------+-----------------------------------------------+--------------+

所以servers/1去了404.有没有办法解决这个问题？

Answer 1

您可以使用方法parameters自定义route中的所有参数。示例：

Route::prefix('teams')->group(function () {
  Route::resource('', 'TeamController')->parameters(['' => 'team']);
});

Answer 2

根据您的评论：

您希望将命名空间和中间件添加到资源路由中。您可以通过在资源控制器的第三个参数中添加middleware和namespace键来实现此目的。

Route::resource('servers', 'ServerController', ['middleware' => 'xyz', 'namespace' => 'xyz']);

修改

如果命名空间不起作用，您可以为控制器分配命名空间。

Route::resource('servers', 'Xyz\ServerController', ['middleware' => 'xyz']);

Laravel 5.4路由组和资源搞乱了参数

2 个答案: