Question

我收到此错误警告：mysqli_error（）正好需要1个参数，给出0 我不明白为什么我的代码会被吹到这里

<?php 
// display add blog script and insert query
} else {

if(isset($_POST['submit']))
{
$heading = htmlentities($_POST['heading']);
$description =  htmlentities($_POST['description']);
$heading = str_replace(' ', '-', $heading);
$cat_name = $_POST['blog_cat'];
$fileToUpload = basename($_FILES['fileToUpload']['name']);
$target_dir = "uploads/blog/";
$target_file = $target_dir.$fileToUpload;
$db_insert_image = "company_profile/".$target_file;
$date = date("y-m-d");
$query = mysqli_query($conn, "INSERT INTO blog SET heading='$heading', 
description='$description', blog_cat='$cat_name', image='$db_insert_image', 
author='$ename', status='1', created_date='$date'");

if ($query) {
if(move_uploaded_file($_FILES["fileToUpload"]["tmp_name"],$target_file)) {
    echo "<script>alert('Image uploaded.')</script>";
    header("location:manageBlog.php");
    exit();
} else {
    echo "<script>alert('There was a problem uploading image.')</script>";
}
} else {
echo mysqli_error();
echo "<script>alert('There was a problem with query, please try again.')
</script>";
}

}

＆GT;

Answer 1

用此替换$ query语句并删除mysqli_error（）行。如果有任何错误，它将自动运行mysqli_error（）。

$query = mysqli_query($conn, "INSERT INTO blog SET heading='$heading', 
description='$description', blog_cat='$cat_name', image='$db_insert_image', 
author='$ename', status='1', created_date='$date'") 
or die(mysqli_error($conn));

Answer 2

您应该将 mysqli_error（）; 更改为 mysqli_error（$ conn）;

有关此功能的更多信息enter link description here

我该如何删除mysqli erro

2 个答案: