Question

我无法弄清楚我在这里做错了什么。我一直在看这个问题的不同视频，并且一直在寻找答案。

当我点击网页上的提交按钮时，字段会被清除，并且不会发生任何其他情况。可能有一个简单的错误，但我无法找出我做错了什么

<a1>
    <h1>Registrer ny bruker</h1>
    <hr>
    <form method="post" action="" >
        <input type="text" name="surName" placeholder="Etternavn" required>
        <br><br>
        <input type="text" name="givenName" placeholder="Fornavn" required>
        <br><br>
        <select name="gender">
            <option value="male">male</option>
            <option value="female">female</option>
        </select>
        <br><br>
        <input type="number" name="age" placeholder="Alder" required>
        <br><br>
        <input type="text" name="mail" placeholder="e-post" required>
        <br><br>
        <input type="text" name="userName" placeholder="Brukernavn" required>
        <br><br>
        <input type="text" name="password" placeholder="Passord" required>
        <br><br>
        <input type="submit" name="submitted" value="Registrer">
    </form>

</a1>
<?php
if(isset($_POST['submitted'])){
    $mysqli = new mysqli('my database username and password');

    $email = $mysqli->real_escape_string($_POST['mail']);
    $surName = $mysqli->real_escape_string($_POST['surName']);
    $givenName = $mysqli->real_escape_string($_POST['givenName']);
    $username = $mysqli->real_escape_string($_POST['userName']);
    $password = md5($_POST['password']);
    $gender = $mysqli->real_escape_string($_POST['gender']);
    $age = $mysqli->real_escape_string($_POST['age']);

    $sql = "INSERT INTO blog_user (first_name, last_name, age, gender, user_password, user_name, mail)
            VALUES ('$givenName','$surName','$age','$gender','$password','$username','$email')
            ";

    $insert = $mysqli->query($sql);
    if ($insert) {
        echo "Succes!";
    } else {
        die("Error: {$mysqli->errno} : {$mysqli->error}");
    }
    $mysqli->close();
}
?>

编辑：当我第一次添加这个时，我做了一个小错字，所以第一个答案并没有解决我的问题。我没有给他们一个投票，我很抱歉我打错了。

Answer 1

    <?php

if(isset($_POST['submitted'])){
    $mysqli = new mysqli('my database username and password');
    $email = $mysqli->real_escape_string($_POST['mail']);
    $surName = $mysqli->real_escape_string($_POST['surName']);
    $givenName = $mysqli->real_escape_string($_POST['givenName']);
    $username = $mysqli->real_escape_string($_POST['userName']);
    $password = md5($_POST['password']);
    $gender = $mysqli->real_escape_string($_POST['gender']);
    $age = $mysqli->real_escape_string($_POST['age']);

    $sql = "INSERT INTO blog_user (first_name, last_name, age, gender, user_password, user_name, mail)
            VALUES ('$givenName','$surName','$age','$gender','$password','$username','$email')
            ";

    $insert = $mysqli->query($sql);
    if ($insert) {
        echo "Succes!";
    } else {
        die("Error: {$mysqli->errno} : {$mysqli->error}");
    }
    $mysqli->close();
}
?>

你错过了if语句。

Answer 2

您的代码是＆＃34;清除字段＆＃34;因为您的表单始终首先显示默认值。 输入字段没有给出默认值，因此＆＃34;清除＆＃34;每次执行你的php文件。

<form method="post" action="" >
<input type="text" name="surName" placeholder="Etternavn" required>
<br><br>
<input type="text" name="givenName" placeholder="Fornavn" required>
<br><br>
<select name="gender">
<option value="male">male</option>
<option value="female">female</option>
</select>
<br><br>
<input type="number" name="age" placeholder="Alder" required>
<br><br>
<input type="text" name="mail" placeholder="e-post" required>
<br><br>
<input type="text" name="userName" placeholder="Brukernavn" required>
<br><br>
<input type="text" name="password" placeholder="Passord" required>
<br><br>
<input type="submit" name="submitted" value="Registrer">
</form>

出于这个原因，您应该在显示表单之前使用表单请求部分

if(isset($_POST['submitted'])){
    $mysqli = new mysqli('my database username and password');
    $email = $mysqli->real_escape_string($_POST['mail']);
    $surName = $mysqli->real_escape_string($_POST['surName']);
    $givenName = $mysqli->real_escape_string($_POST['givenName']);
    $username = $mysqli->real_escape_string($_POST['userName']);
    $password = md5($_POST['password']);
    $gender = $mysqli->real_escape_string($_POST['gender']);
    $age = $mysqli->real_escape_string($_POST['age']);

    $sql = "INSERT INTO blog_user (first_name, last_name, age, gender, user_password, user_name, mail)
            VALUES ('$givenName','$surName','$age','$gender','$password','$username','$email')
            ";

    $insert = $mysqli->query($sql);
    if ($insert) {
        echo "Succes!";
    } else {
        die("Error: {$mysqli->errno} : {$mysqli->error}");
    }
    $mysqli->close();
}

并显示类似这样的默认值...

<form method="post" action="" >
<input type="text" name="surName" placeholder="Etternavn" 
required value="<?php echo $surName;?>">
<br><br>
<input type="text" name="givenName" placeholder="Fornavn" 
required value="<?php echo $givenName;?>">

<强>等...

注意数据库查询应该使用预准备语句来避免sql 注射。

Answer 3

试试这个......

<?php
   if(isset($_POST['submitted'])){

（isset（$ _ POST ['submitted']））似乎不起作用

3 个答案: