Count Distinct - Inner Join - Group By / With新的Linq-to-NHibernate Provider

时间:2010-12-03 02:42:18

标签: sql linq nhibernate linq-to-nhibernate

您如何使用新的Linq-to-NHibernate Provider(3.x)编写这个确切的SQL查询

SELECT Post.Title, COUNT(DISTINCT Comment.UserId)
FROM Post
INNER JOIN Comment ON Post.Id = Comment.PostId
GROUP BY Post.Title

如果你想进行一些测试,这里有一些SQL

DECLARE @Post Table(Id int identity(1,1), Title varchar(200))
DECLARE @Comment Table(Id int identity(1,1), PostId int, Comment varchar(200), UserId int)

DECLARE @PostId int

INSERT INTO @Post(Title)
VALUES ('Test')

SELECT @PostId = SCOPE_IDENTITY()

INSERT INTO @Comment(PostId, Comment, UserId)
VALUES (@PostId, 'Test Comment', 1)

INSERT INTO @Comment(PostId, Comment, UserId)
VALUES (@PostId, 'Test Comment 2', 1)

INSERT INTO @Comment(PostId, Comment, UserId)
VALUES (@PostId, 'Test Comment 3', 2)

INSERT INTO @Post(Title)
VALUES ('Test 2')

SELECT @PostId = SCOPE_IDENTITY()

INSERT INTO @Comment(PostId, Comment, UserId)
VALUES (@PostId, 'Test Comment', 1)

INSERT INTO @Comment(PostId, Comment, UserId)
VALUES (@PostId, 'Test Comment 2', 2)

INSERT INTO @Comment(PostId, Comment, UserId)
VALUES (@PostId, 'Test Comment 3', 3)


SELECT Post.Title, COUNT(DISTINCT Comment.UserId)
FROM @Post Post
INNER JOIN @Comment Comment ON Post.Id = Comment.PostId
GROUP BY Post.Title

1 个答案:

答案 0 :(得分:2)

我认为目前不可能执行count(distinct x)部分。

这是我最接近的:

from comment in session.Query<Comment>()
group comment by comment.Post.Title
      into g
      select new
             {
                 Title = g.Key,
                 Count = g.Select(x => x.UserId).Distinct().Count()
             };

但它产生与SQL完全相同的SQL:

from comment in session.Query<Comment>()
group comment by comment.Post.Title
      into g
      select new
             {
                 Title = g.Key,
                 Count = g.Count()
             };

这是:

SELECT Post.Title, COUNT(*)
FROM Comment
LEFT JOIN Post ON Post.Id = Comment.PostId
GROUP BY Post.Title

您应该将问题发布到http://jira.nhforge.org。 Linq提供商正在进行大量的工作,并且很有可能在不久的将来支持这种结构。