我正试图在POS系统上提取所有待售物品。
我有几张桌子需要加入并订购/分组。我希望我能解释一下。
Table `items`:
+---------+--------+
| item_id | Name |
+---------+--------+
| 33 | Thing1 |
| 34 | Thing2 |
| 54 | Thing3 |
| 67 | Thing4 |
+---------+--------+
Table `kits`:
+-------------+------+
| item_kit_id | Name |
+-------------+------+
| 1 | Kit1 |
| 2 | Kit2 |
+-------------+------+
Table `sales`:
+---------+-------------+---------+
| sale_id | sale_date | Total |
+---------+-------------+---------+
| 1 | 2016-06-11 | 100.00 |
| 2 | 2016-06-12 | 145.00 |
+---------+-------------+---------+
Table `sale_items`:
+-----+---------+----------+---------+
| id | sale_id | line_num | Item_id |
+-----+---------+----------+---------+
| 1 | 1 | 1 | 33 |
| 2 | 1 | 3 | 54 |
| 3 | 2 | 1 | 34 |
| 4 | 2 | 2 | 67 |
+-----+---------+----------+---------+
Table `sale_kit_items`:
+-----+---------+----------+-------------+
| id | sale_id | line_num | item_kit_id |
+-----+---------+----------+-------------+
| 1 | 1 | 2 | 1 |
| 2 | 2 | 3 | 2 |
+-----+---------+----------+-------------+
我希望结果看起来像
Results:
+---------+----------+---------+-------------+
| sale_id | line_num | item_id | item_kit_id |
+---------+----------+---------+-------------+
| 1 | 1 | 33 | null |
| 1 | 2 | null | 1 |
| 1 | 3 | 54 | null |
| 2 | 1 | 54 | null |
| 2 | 2 | 67 | null |
| 2 | 3 | null | 2 |
+---------+----------+---------+-------------+
如果我能得到的话,甚至会更好:
Results:
+---------+----------+---------+-------------+--------+
| sale_id | line_num | item_id | item_kit_id | name |
+---------+----------+---------+-------------+--------+
| 1 | 1 | 33 | null | Thing1 |
| 1 | 2 | null | 1 | Kit1 |
| 1 | 3 | 54 | null | Thing2 |
| 2 | 1 | 54 | null | Thing3 |
| 2 | 2 | 67 | null | Thing4 |
| 2 | 3 | null | 2 | Kit2 |
+---------+----------+---------+-------------+--------+
答案 0 :(得分:1)
我花了一些时间来了解你的情景...
编辑
也许您应该将items
和sale_kit_items
的LEFT JOIN更改为INNER JOIN(我希望ID可以在相应的表中找到)。
select s.sale_id, si.line_num, si.item_id, null as item_kit_id, i.name
from sales s
left join sale_items si on s.sale_id = si.sale_id
left join items i on si.item_id = i.item_id
union all
select s.sale_id, ski.line_num, null as item_id, ski.item_kit_id, k.name
from sales s
left join sale_kit_items ski on s.sale_id = ski.sale_id
left join kits k on ski.item_kit_id = k.item_kit_id
order by 1, 2
;