Question

我已经编写了这个脚本来搜索特定用户拥有的文件 - 除了这个函数之外，它工作得很好，返回所有结果，并且链接被设置为像doc一样打开。所以pdf和其他文件因为URL错误而导致错误打开。有没有通用的方法来打开文件，还是我需要编写if语句？关于如何解决这个问题的任何可能的想法？感谢

    function handleResults(results){
         console.log('Handle Results was called! ');
         document.writeln('<a href="https://script.google.com/a/macros/35634534534534534534534534534">BACK</a><br/><br/>');
         var length=results.length; // total elements of results
         for(var i=0;i<length;i++)
         {
         var item=results[i];
         item=item.split("|~|"); // split the line |~|, position 0 has the filename and 1 the file id
         
         document.writeln("<b><a href='https://docs.google.com/document/d/"+item[1]+"' target='_blank'>"+item[0]+"</b></a> (Last modified: "+item[2]+")<br/><br/>"); // write result
        
        }
        document.writeln("End of results...");
       }

Answer 1

感谢@spiderPig使用File.getUrl（）;

function handleResults(results){
         console.log('Handle Results was called! ');
         document.writeln('<a href="https://script.google.com/a/macros/35634534534534534534534534534">BACK</a><br/><br/>');
         var length=results.length; // total elements of results
         for(var i=0;i<length;i++)
         {
         var item=results[i];
         item=item.split("|~|"); // split the line |~|, position 0 has the filename and 1 the file URL
         // i changed item1 to contain the file.getUrl instead of the fileId
         document.writeln("<b><a href='"+item[1]+"' target='_blank'>"+item[0]+"</b></a> (Last modified: "+item[2]+")<br/><br/>"); // write result
        
        }
        document.writeln("End of results...");
       }

Web应用程序链接以查看驱动器中的任何文件

1 个答案: