Question

我想实现一个web服务，它在request-payload中只使用一个命名参数。在curl视图中它应该像： curl -X PATCH myurl.net/my_service -d“{mySingleParameter：49}”

我正在尝试使用Spring，但我想知道要将此类有效负载映射到我的方法，我必须声明一个新类。像：

...
public static class PayloadWithSingleParamMSP{
  public Long mySingleParameter;
}

@RequestMapping(value = "my_service", method = RequestMethod.PATCH)
public String myService(@RequestBody PayloadWithSingleParamMSP payload){
  Long valueWhichIReallyNeed = payload.mySingleParameter;
  //do job
  ...
}
...

但有没有办法直接获取我真正需要的价值（mySingleParameter）？

Answer 1

你有几个选择：

    @RequestMapping(value = "my_service", method = RequestMethod.PATCH)
    public String myService(@RequestBody ObjectNode payload){
        Long valueWhichIReallyNeed = payload.get("mySingleParameter").asLong();
        //do job
       ...
    }

或

@RequestMapping(value = "my_service", method = RequestMethod.PATCH)
public String myService(@RequestBody Map<String, String> payload){
    Long valueWhichIReallyNeed = Long.parseLong(payload.get("mySingleParameter"));
    //do job
    ...
}

甚至

@RequestMapping(value = "my_service", method = RequestMethod.PATCH)
public String myService(@RequestBody  Long mySingleParameter){
    Long valueWhichIReallyNeed = mySingleParameter;
    //do job
    //  ...
}

但在最后一种情况下，您的卷曲将如下所示：

curl -X PATCH myurl.net/my_service -d "49"

在此问题的答案中，您可以找到更多选项：Passing multiple variables in @RequestBody to a Spring MVC controller using Ajax

Spring：只有一个元素的request-payload

1 个答案: