Question

我有一个包含团队成员的对象。

如果incomingMessage包含其中一个键，那么我想返回一条关于它们的消息。

有没有办法可以在下面的代码中获得匹配的密钥？

const team = {
  hank: ['good guy', 'wonderful man'],
  chuck: ['jerk', 'buttmunch']
}

let incomingMessage = 'tell me about chuck';

if(Object.keys(team).indexOf(incomingMessage) > -1) {
  console.log(team);
  //is there a way here that I can get the 
  //key that has matched? so in this case, 'chuck'
}

Answer 1

逻辑向后......您需要检查消息中是否存在密钥，而不是相反。

类似的东西：

Object.keys(team).forEach(function(key) {
   if (incomingMessage.indexOf(key) > -1){
      console.log('Found ' + key +' in message')
   }
});

Answer 2

我会使用for in循环来遍历团队的属性，然后在其中使用indexOf。

const team = {
  hank: ['good guy', 'wonderful man'],
  chuck: ['jerk', 'buttmunch']
}

let incomingMessage = 'tell me about chuck';

for (var member in team) {
  if (incomingMessage.indexOf(member) > -1) {
      console.log(team[member]); // your team member information array
 }
}

Answer 3

var arrRecTeam = incomingMessage.split(' ');
var arrTeam = Object.keys(team)


arrTeam.forEach((val, key) => console.log("found at", arrRecTeam.indexOf(val)))

Answer 4

您的逻辑是相反的，您需要查找字符串中的键，而不是键中的字符串。

＆＃13;

angular.module('App', [])
  .directive('dir', function () { 
    return {
        restrict: 'E',
        template: `
          <div ng-transclude="header"></div>
          <div class="static-content">
            Lorem ipsum dolor sit amet, consectetur adipiscing elit.
          </div>

          <div ng-transclude="footer">
        `,
        transclude: {
            'header': '?dirHeader',
            'footer': '?dirFooter'
        },
        link: function ($s, $el, $attrs, thisCtrl, $transclude) {
          console.log($transclude.isSlotFilled('header'))
          console.log($transclude.isSlotFilled('footer'))
        }
    };
  });

＆＃13;

Answer 5

const team = {
  hank: ['good guy', 'wonderful man'],
  chuck: ['jerk', 'buttmunch']
}

var incomingMessage = 'tell me about chuck';

if(incomingMessage.indexOf(Object.keys(team)) > -1) {
  alert(team);
  //is there a way here that I can get the 
  //key that has matched? so in this case, 'chuck'
}

获取Object.keys（obj）

5 个答案: