我正在处理httpwebrequest中的超时错误等问题,但它一直在调试中抛出错误,这意味着我无法在我的应用程序中显示状态代码。我试图使用Try catch,但是当我试图抓住postresponse状态代码。我从catch中得到的唯一一件事就是我在调试中看到的错误描述,而不是响应的状态代码..
更新:(我最终做到了这一点......我仍然无法获得不同的状态代码,但我会这样做)
Try
postresponse = DirectCast(postreq.GetResponse, HttpWebResponse)
Dim postreqreader As New StreamReader(postresponse.GetResponseStream())
data = postreqreader.ReadToEnd
'Get title
Dim reg = New Regex("<title>(.*?)</title>")
Dim matches = reg.Matches(data)
Dim wtitle As String = "No title"
For Each mat As Match In matches
wtitle = mat.Value.Replace("<title>", "").Replace("</title>", "")
Next mat
ListView1.Items(ci).SubItems(3).Text = wtitle
'OK
ListView1.Items(ci).SubItems(1).Text = "OK"
Catch ex As Exception When WebExceptionStatus.Timeout
ListView1.Items(ci).SubItems(1).Text = "Timeout"
Catch ox As Exception When WebExceptionStatus.NameResolutionFailure
MsgBox("Name resolution failure")
End Try
原件:
Dim data As String = Nothing
Try
Dim postreq As HttpWebRequest = DirectCast(HttpWebRequest.Create(url), HttpWebRequest)
postreq.Method = "GET"
postreq.KeepAlive = True
postreq.Timeout = 5000 '10s
postreq.UserAgent = "Mozilla/5.0 (Windows; U; Windows NT 6.1; ru; rv:1.9.2.3) Gecko/20100401 Firefox/4.0 (.NET CLR 3.5.30729"
postreq.ContentType = "application/x-www-form-urlencoded"
postreq.Referer = "https://www.facebook.com"
Dim postresponse As HttpWebResponse
postresponse = DirectCast(postreq.GetResponse, HttpWebResponse)
If postresponse.StatusCode = HttpStatusCode.OK Then
Dim postreqreader As New StreamReader(postresponse.GetResponseStream())
data = postreqreader.ReadToEnd
'Get title
Dim reg = New Regex("<title>(.*?)</title>")
Dim matches = reg.Matches(data)
Dim wtitle As String = "No title"
For Each mat As Match In matches
wtitle = mat.Value.Replace("<title>", "").Replace("</title>", "")
Next mat
ListView1.Items(ci).SubItems(3).Text = wtitle
'OK
ListView1.Items(ci).SubItems(1).Text = "OK"
Else
ListView1.Items(ci).SubItems(1).Text = "Fejl"
End If
Catch ex As Exception
MsgBox(ex.ToString)
End Try
答案 0 :(得分:3)
ex
异常对象属于通用Exception
类型,它不提供任何HttpWebRequest特定信息。为WebException
对象添加catch块:
Try
' ..........
Catch ex As WebException
If ex.Status = WebExceptionStatus.Timeout Then
MsgBox("The request has timed out!")
Else
MsgBox(ex.Status)
End If
Catch ex As Exception
MsgBox(ex.ToString)
End Try