Question

这是table1中的数据column1

“errorList”： “017519033：的 815 下，”， “的errorCode”： “139”
“errorList”： “0115101233：的 815 下，”， “的errorCode”： “139”
“errorList”： “01815081233：的 805 下，”， “的errorCode”： “19”
“errorList”： “018995081233：的 805 下，”， “的errorCode”： “815”

我想在“：”之后选择包含815的数据任何想法怎么做？

我的预期输出：

“errorList”： “017519033：的 815 下，”， “的errorCode”： “139”
“errorList”： “0115101233：的 815 下，”， “的errorCode”： “139”

Answer 1

如何关注

select * from table1 where column1 like 'errorList":"%:815%'

Answer 2

您可以使用Like或CharIndex

SELECT * FROM yourTable WHERE column1 LIKE '%:815%'

OR

SELECT * FROM yourTable WHERE charindex(':815', column1) > 0

Answer 3

这应该有效：

select * from mytable where column1 like '%:815,%'

Answer 4

select * from your_table 
where 
right(errorList, len(errorlist) - charindex(':', errorlist)) = 815

Answer 5

另一种使用XML进行字符串拆分的解决方案：

DECLARE @tbl TABLE(YourString VARCHAR(100));
INSERT INTO @tbl VALUES
 ('"errorList":"017519033:815,","errorCode":"139"')
,('"errorList":"0115101233:815,","errorCode":"139"')
,('"errorList":"01815081233:805,","errorCode":"19"')
,('"errorList":"018995081233:805,","errorCode":"815"');


SELECT *
FROM @tbl 
WHERE LEFT(CAST('<x>' + REPLACE(YourString,':','</x><x>') + '</x>' AS XML).value('(/x)[3]','nvarchar(max)'),3)='815'

这种方法的最大优点是，您可以使用索引访问字符串的任何部分，在许多情况下是类型安全的......

更新检查

DECLARE @tbl TABLE(ID INT IDENTITY,YourString VARCHAR(100));
INSERT INTO @tbl VALUES
 ('"errorList":"017519033:815,","errorCode":"139"')
,('"errorList":"0115101233:815,","errorCode":"139"')
,('"errorList":"01815081233:805,","errorCode":"19"')
,('"errorList":"018995081233:805,","errorCode":"815"');

WITH Casted AS
(
    SELECT ID
          ,YourString
          ,CAST('<x>' + REPLACE(REPLACE(YourString,'"',''),':','</x><x>') + '</x>' AS XML) AS TheXml
    FROM @tbl
)
SELECT TheXml.value('(/x/text())[1]','nvarchar(max)') AS Part1
      ,TheXml.value('(/x/text())[2]','nvarchar(max)') AS Part2
      --,TheXml.value('(/x/text())[3]','nvarchar(max)') AS Part3
      ,Part3a AS Part3
      ,Part3b AS Part4
      ,TheXml.value('(/x/text())[4]','nvarchar(max)') AS Part5
FROM Casted
CROSS APPLY(SELECT TheXml.value('(/x/text())[3]','nvarchar(max)') AS Part3
                  ,CHARINDEX(',',TheXml.value('(/x/text())[3]','nvarchar(max)')) AS PosComma) AS A
CROSS APPLY(SELECT LEFT(Part3,A.PosComma-1) AS Part3a
                  ,SUBSTRING(Part3,A.PosComma+2,1000) AS Part3b) AS B

结果

Part1       Part2           Part3   Part4       Part5
errorList   017519033       815     errorCode   139
errorList   0115101233      815     errorCode   139
errorList   01815081233     805     errorCode   19
errorList   018995081233    805     errorCode   815

Answer 6

select * from table1 where PATINDEX('%:815%',column1)>1

仅在特殊字符串之前选择String

6 个答案:

更新检查