Question

我是python的新手，请有人帮忙绘制如下形状。程序必须以星号作为输入。

星数= 7

*      *
**    **
***  *** 
********
***  *** 
**    **
*      *

我的代码：

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, pattern_size):
    pattern = list(" " * pattern_size)
    pattern[:t] = "*" * t
    pattern[-t:] = '*' * t
    print(''.join(pattern))

star count :  9
*        *
**      **
***    ***
****  ****
**********
**********
**********
**********
**********

Answer 1

这是一个易于理解的示例，使用您的方法使用两个for循环：一个只是另一个的反转

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, int(pattern_size/2)):
    pattern = list(" " * pattern_size)
    pattern[:t] = "*" * t
    pattern[-t:] = '*' * t
    print(''.join(pattern))

for t in range(int(pattern_size/2), 0, -1):
    pattern = list(" " * pattern_size)
    pattern[:t] = "*" * t
    pattern[-t:] = '*' * t
    print(''.join(pattern))

更高级的方法是使用字符串方法.center()，如下所示：

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, int(pattern_size/2)):
    print((" " * (pattern_size-t*2)).center(pattern_size, '*'))
for t in range(int(pattern_size/2), 0, -1):
    print((" " * (pattern_size - t * 2)).center(pattern_size, '*'))

Answer 2

就像我的评论一样，这是完整的代码：

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, pattern_size):
    pattern = list(" " * pattern_size)
    len_t = t if t <= (pattern_size / 2) else (pattern_size - t)
    pattern[:len_t] = "*" * len_t
    pattern[-len_t:] = '*' * len_t
    print(''.join(pattern))

希望得到这个帮助。

如何绘制如下的'x'形状

2 个答案: