Question

我正在尝试从mysql数据库中获取并显示所有用户信息，但它无法显示行上的时间，但可以显示其他信息，如用户ID和用户名。如果我在我的windows localhost中运行系统它只是工作正常但是当我使用网络托管运行它时它没有显示日期。

数据库：

数据库记录：

我目前的编码：

<?php
    $sql_select = "SELECT * FROM tbluserinfo";
    $result = $conn->query($sql_select);
    if ($result->num_rows > 0) 
    {
        while($row = $result->fetch_assoc()) 
        {
            echo "<tr>";
            echo "<td>".$row['user_id']."</td>";
            echo "<td>".$row['user_name']."</td>";
            echo "<td>".$row['user_created_date']."</td>";
            echo "</tr>";
        }
    }
    else
    {
        echo "<td colspan='3' style='color: red;'>No record found.</td>";
    }
?>

Answer 1

你可以尝试：

ALTER PROCEDURE [dbo].[GetDataLastValue]
    @InstrumentID INT
AS
BEGIN
    SELECT 
        InstrumentId, 
        c.ChannelId, c.DataTime,  
        CONVERT(DECIMAL(38, 4), (NumericValue / c.Scale)) AS NumericValue, 
        c.Diag, ChannelDescription
    FROM 
        dbo.Instrument 
    LEFT JOIN 
       (SELECT 
            ChannelId,
            MAX(DateTime) as DataTime,
            (SELECT TOP 1 NumericValue 
             FROM dbo.Datum 
             WHERE ChannelId = t.ChannelId 
             ORDER BY DateTime DESC) AS NumericValue,
            (SELECT TOP 1 InstrumentId 
             FROM dbo.Channel 
             WHERE Channel.ChannelId = t.ChannelId) AS myinst,
            (SELECT Scale 
             FROM dbo.Channel 
             WHERE Channel.ChannelId = t.ChannelId) AS Scale,
            (SELECT Diag 
             FROM dbo.Channel 
             WHERE Channel.ChannelId = t.ChannelId) AS Diag,
           (SELECT ChannelDescription 
            FROM dbo.Channel 
            WHERE Channel.ChannelId = t.ChannelId) AS ChannelDescription 
       FROM  
           dbo.Datum as t 
       GROUP BY ChannelId) c ON c.myinst = Instrument.InstrumentId 
    WHERE 
        InstrumentId = @InstrumentID AND c.Diag = 0
    ORDER BY 
        ChannelDescription
END

并确保您的echo date('j F, Y', strtotime($row['user_created_date']));不为空，否则会为您提供此日期：

$row['user_created_date']

日期无法显示

1 个答案: