Question

我想从字符串中删除所有形式的网址，如果它们以.*://或www.*开头，但在将正则表达式添加到预先存在的复杂模式时遇到问题。

目前，我使用

public static String censorUrls(String str) {

        String urlPattern = "((https?|ftp|gopher|telnet|file|Unsure|http):((//)|(\\\\))+[\\w\\d:#@%/;$()~_?\\+-=\\\\\\.&]*)";
        Pattern pattern = Pattern.compile(urlPattern,Pattern.CASE_INSENSITIVE);
        Matcher matcher = pattern.matcher(str);

        int i = 0;

        while ( matcher.find() ) {

            str = str.replaceAll(matcher.group(i), "****").trim();

            i++;

        }

    return str;

}

但是，对于可能只是www.google.com或google.com甚至www3.site.com

的网址，这无效

Answer 1

无法记住它的来源，但你可以尝试一下。

如果它的中间字符串匹配与否，您可能可以使用此字符串这使用空白边界。 (?<!\S)和(?!\S)并将在锚点匹配职位也是如此。

原始：(?i)(?<!\S)(?!mailto:)(?:[a-z]*://)?(?:\S+(?::\S*)?@)?(?:(?:(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\x{a1}-\x{ffff}0-9]+-?)*[a-z\x{a1}-\x{ffff}0-9]+)(?:\.(?:[a-z\x{a1}-\x{ffff}0-9]+-?)*[a-z\x{a1}-\x{ffff}0-9]+)*(?:\.(?:[a-z\x{a1}-\x{ffff}]{2,})))|localhost)(?::\d{2,5})?(?:\/[^\s]*)?(?!\S)

弦乐："(?i)(?<!\\S)(?!mailto:)(?:[a-z]*://)?(?:\\S+(?::\\S*)?@)?(?:(?:(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\x{a1}-\\x{ffff}0-9]+-?)*[a-z\\x{a1}-\\x{ffff}0-9]+)(?:\\.(?:[a-z\\x{a1}-\\x{ffff}0-9]+-?)*[a-z\\x{a1}-\\x{ffff}0-9]+)*(?:\\.(?:[a-z\\x{a1}-\\x{ffff}]{2,})))|localhost)(?::\\d{2,5})?(?:\\/[^\\s]*)?(?!\\S)"

格式化：

 (?i)
 (?<! \S )
 (?! mailto: )
 (?:
      [a-z]* :
      \/\/
 )?
 (?:
      \S+ 
      (?: : \S* )?
      @
 )?
 (?:
      (?:
           (?:
                [1-9] \d? 
             |  1 \d\d 
             |  2 [01] \d 
             |  22 [0-3] 
           )
           (?:
                \.
                (?: 1? \d{1,2} | 2 [0-4] \d | 25 [0-5] )
           ){2}
           (?:
                \.
                (?:
                     [1-9] \d? 
                  |  1 \d\d 
                  |  2 [0-4] \d 
                  |  25 [0-4] 
                )
           )
        |  (?:
                (?: [a-z\x{a1}-\x{ffff}0-9]+ -? )*
                [a-z\x{a1}-\x{ffff}0-9]+ 
           )
           (?:
                \.
                (?: [a-z\x{a1}-\x{ffff}0-9]+ -? )*
                [a-z\x{a1}-\x{ffff}0-9]+ 
           )*
           (?:
                \.
                (?: [a-z\x{a1}-\x{ffff}]{2,} )
           )
      )
   |  localhost
 )
 (?: : \d{2,5} )?
 (?: \/ [^\s]* )?
 (?! \S )

从String中删除URL

1 个答案: