Question

我有一个比赛表，其中包含足球（足球）部门的所有历史比赛。大约有30000场比赛，我的挑战是为特定球队和其他球队找回胜利，平局和输球。

对于我的问题，我只是使用绘图，为了检索我的绘图我有两种可能的场景：

该团队是主队
该团队是客队

所以根据我的数据，我的团队是主队的第一个场景的查询是这样的：

SELECT 
    matches.away_team as VS, 
    COUNT(matches.idmatch) AS TIES 
FROM
    my_football_database.matches 
WHERE 
    home_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
GROUP BY 
    away_team 
LIMIT 5;

输出：

+------+------+
| VS   | TIES |
+------+------+
|    2 |    1 |
|    3 |    3 |
|    4 |    2 |
|    8 |    1 |
|    9 |    3 |
+------+------+

第二种情况是我的团队是客队，所以它是这样的：

SELECT 
    matches.home_team as VS, 
    COUNT(matches.idmatch) AS TIES 
FROM
    my_football_database.matches 
WHERE 
    away_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
GROUP BY 
    home_team 
LIMIT 5;

输出：

+------+------+
| VS   | TIES |
+------+------+
|    2 |    4 |
|    3 |    2 |
|    7 |    1 |
|    8 |    3 |
|    9 |    1 |
+------+------+

正如您所见：

当我的球队（ID = 14）作为主队对阵球队ID = 3时，共有3场比赛以平局结束
在第二个结果中，当我的球队（ID = 14）作为客场球队与球队ID = 3比赛时，共有2场比赛以平局结束

如何根据“VS”ID来总结TIES的结果？比如，在列出作为主队的球队的所有领带之后，由客队分组并列出球队作为客队进行比赛的所有领带，由主队分组，根据“Vs”ID加入两个列。

这种情况下的示例结果是：

+------+------+
| VS   | TIES |
+------+------+
|    2 |    5 |
|    3 |    5 |
|    4 |    2 |
|    7 |    1 |
|    8 |    4 |
|    9 |    4 |
+------+------+

注意：我必须指出一个单一的查询，可以给我一张表格，其中列出了给定团队的所有胜利，失败和平局，并按照他们对战的球队进行分组。

这是总共14个场景。 Home and Away Draws（2），Home and Away赢得常规，奖励和惩罚（6）。 Home and Away失去正常，奖励和处罚（6）。

因此，我不是在寻找可以解决Draws交易的代码，而是更像是关于该问题的研究，研究或实施的HINT。我的第一个想法是分别创建每个场景，然后将它们用作子查询，但我被告知这对性能不方便。

Answer 1

使用两个查询中的UNION，然后将行与VS列相加。

SELECT VS, SUM(TIES) AS TIES
FROM (
    (SELECT matches.away_team as VS, count(matches.idmatch) as TIES 
    from my_football_database.matches WHERE home_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
    GROUP BY away_team 
    LIMIT 5)
    UNION ALL
    (SELECT matches.home_team as VS, count(matches.idmatch) as TIES 
    from my_football_database.matches WHERE away_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
    GROUP BY home_team 
    LIMIT 5)) AS u
GROUP BY VS

Answer 2

使用CASE构造：

select 
  otherteam,
  count(case when mygoals > othergoals then 1 end) as won,
  count(case when mygoals = othergoals then 1 end) as ties,
  count(case when mygoals < othergoals then 1 end) as lost
from
(
  select
    11 as myteam,
    case when home_team = 11 then away_team else home_team end as otherteam,
    case when home_team = 11 then home_team_goals else away_team_goals end as mygoals,
    case when home_team = 11 then away_team_goals else home_team_goals end as othergoals
  from mydb.matches
  where (home_team = 11 or away_team = 11)
) whoiswho
group by otherteam;

（哎呀，对不起，我猜这比“像一个提示”略多。）

如何根据Group BY列对两个查询的结果求和？

2 个答案: