Question

我有一个巨大的文本文件，如下所示：

36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,3
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,8
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,14
36,53,15596,0.58454577855,0.26119,2.24878677855,0.116147072052964,12

所需的输出是：

36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-03
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-08
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-14
36,53,15596,0.58454577855,0.26119,2.24878677855,0.116147072052964,MI-12

我在这里以及其他社区尝试了其他相关帖子，但无法完全得到我想要的内容。

更新

这是cross-question（我想要Unix / perl答案和批处理/ powershell解决方案。）这些答案很有趣。

Answer 1

如果你喜欢PS，这是一个PowerShell答案。

// Calculate Form Fields

$("input.price").on("keyup", function(){
  $(this).siblings("input.total").val((

    $(this).val() * $(this).siblings("input.qty").val()
  ).toFixed(2));
});

$("input.qty").on("keyup", function(){

  $(this).siblings("input.total").val((

    $(this).val() * $(this).siblings("input.price").val()
  ).toFixed(2));
});

Answer 2

下一个代码会执行您想要的操作，除非在小于10时填充零最后一个标记，希望它有所帮助。

编辑：当最后一个数字小于10时，我想出了一种方法来插入一个前导零点。有点难看，但它确实如此。：）

@echo off

setlocal EnableDelayedExpansion

for /F "delims=, tokens=1-8" %%A in (f.txt) do (
    set /a "t=%%H-10"
    if "!t:~0,1!" equ "-" (set "n=0%%H") else (set "n=%%H")
    echo(%%A,%%B,%%C,%%D,%%E,%%F,%%G,MI-!n!>>f.new.txt
)

move /Y f.new.txt f.txt >nul 2>&1

对于文件（在本例中为f.txt）：

36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,3
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,8
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,14
36,53,15596,0.58454577855,0.26119,2.24878677855,0.116147072052964,12

产生以下结果（也在f.txt中）：已更新

36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-03
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-08
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-14
36,53,15596,0.58454577855,0.26119,2.24878677855,0.116147072052964,MI-12

Answer 3

这是一个GET https://outlook.office.com/api/v1.0/me/MailFolders/INBOX/messages GET https://outlook.office.com/api/v1.0/me/MailFolders/SentItems/messages批处理文件，依赖于一个很好的黑客来分割逗号分隔列表的最后一项，与字符串中出现的逗号数量无关。基本技术如下所示;请注意，这需要启用delayed expansion：

cmd

以下是脚本的代码，将上述方法保存在名为set "x=This,is,the,original,list." set "y=" & set "z=%x:,=" & set "y=!y!,!z!" & set "z=%" & set "y=!y:~1!" echo ORIGINAL: %x% echo LAST ITEM: %z% echo REMAINDER: %y%的子例程中：

:GET_LAST_ITEM

Answer 4

这是@RomanPerekhrest在我的交叉问题中提供的答案（寻求unix / perl解决方案）here：

使用sprintf函数进行awk方法（添加前导零）：
get '/', to: redirect('https://www.openhub.net/'), constraints: { subdomain: 'code' }
输出：
 awk -F, -v OFS=',' '$8="MI-"sprintf("%02d",$8);' file

用字符串替换最后一个逗号后的最后一个字符

4 个答案: