多个Ajax表单数据上载Jquery

时间:2017-04-13 13:03:40

标签: javascript java ajax jsp file-upload

我正在尝试将多个文件上传到一个文件夹,因为我在日志中收到错误,所以这很有效:"必需的MultipartFile参数' file'不存在"。请看下面的代码并指导我出错的地方。

<input type="file" id = 'attachmentFileUploadInput' multiple style="display: none;" >

    function makeProgress(number){   
      var url = getRelativeURL("web/fileUpload");        
      var formData = new FormData();
      formData.append('number', number);
      fls = document.getElementById("attachmentFileUploadInput").files; //length of files... 
      for(j=0;j<fls.length;j++){
          formData.append('files[]', fls[j]);  //note files[] not files
      }
      // this wroked for single file upload -formData.append('file', $('input[type=file]')[0].files[0]); 
      console.log("form data " + formData);
      $.ajax({
          url : url,
          data : formData,
          processData : false,
          contentType : false,
          type : 'POST',
          success : function(data) {
           FileUploadVisible(true);
           $('#attachmentModal').modal('hide')
           $(':input','#attachmentModal').val("");
            $("#pbarmain").hide();
            $("#pbar").hide();
            $("#actionPlanDiv").hide();
            setObjectEnabled('#Upload',false);
          },
          error : function(err) {
              FileUploadErrorVisible(true);
          }
     });

        }

服务器端:

private static String UPLOADED_FOLDER = "C://temp//";

@RequestMapping(value = { "/fileUpload" }, method = RequestMethod.POST)
@ResponseBody
public String uploadFile( @RequestParam("number") String number, @RequestParam("file") MultipartFile file, MultipartHttpServletRequest req, HttpServletResponse res)
{       
    try {
        File directory = new File(UPLOADED_FOLDER + number);
                if (! directory.exists()){
                    directory.mkdir();
                  }
            byte[] bytes = file.getBytes();
            Path path = Paths.get(UPLOADED_FOLDER + number + "//" + file.getOriginalFilename());
            Files.write(path, bytes);
            logger.info("You have successfully uploaded '" + file.getOriginalFilename() + "'");
            return("File Uploaded");


    } catch (Exception e) {
        res.setStatus(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
        logger.error("Failed to upload file '" + file.getOriginalFilename() + "'", e);
        return("File Not Uploaded");
    }
}

}

1 个答案:

答案 0 :(得分:0)

contentType: 'multipart/form-data'这就是你所缺少的