Question

我在访问XML标记的值时遇到问题。这是和XML文件部分：

    <VAST version="3.0">
<Ad id="192347">
<InLine>
<AdSystem version="1.0">Appnext VAST</AdSystem>
<AdTitle>Empire: Four Kingdoms</AdTitle>
<Impression>
https://admin.appnext.com/pView.aspx?b=192347&z=25526&c=125501&tid=vast
</Impression>
<Description>
Become a mighty emperor of the four kingdoms in this award-winning MMO strategy game!
</Description>
<Pricing>"cpi","USD","1.407"</Pricing>
<Error>
https://admin.appnext.com/tp12.aspx?ads_type=VAST&tid=VAST&vid=1&pid=0fa643ba-a3e5-4f01-bf49-89354fbd0562&ref=error&bid=192347&cid=125501
</Error>
<Creatives>
<Creative id="192347">
<Linear>
<Duration>00:00:30.000</Duration>
<VideoClicks>...</VideoClicks>
<TrackingEvents>...</TrackingEvents>
<MediaFiles>
<MediaFile delivery="progressive" type="video/mp4" width="640" height="360" bitrate="500" scalable="true" maintainAspectRatio="true">
<![CDATA[
https://appnext-a.akamaihd.net/banner/video/video-192347-30_o.mp4?rnd=1488986809
]]>
</MediaFile>
<MediaFile delivery="progressive" type="video/mp4" width="320" height="180" bitrate="500" scalable="true" maintainAspectRatio="true">
<![CDATA[
https://appnext-a.akamaihd.net/banner/video/video-192347-30.mp4?rnd=1488986813
]]>
</MediaFile>
</MediaFiles>
</Linear>
</Creative>``

我需要访问MediaFile标记值，但我只获取属性值，如：delivery，type等。这是我已经做过的代码：

$xml = file_get_contents('https://admin.appnext.com/offerWallApi.aspx?id=0fa643ba-a3e5-4f01-bf49-89354fbd0562&type=vast&vast_ver=3.0&tid=vast&cv=1&duration=all&pbk=test&ip=8.8.8.8', false, $context);
    $response = simplexml_load_string($xml);
    $files = $response->Ad->InLine->Creatives->Creative->Linear->MediaFiles->MediaFile;
    foreach($files as $file) {
        var_dump($file);
    }

PHP响应：

object（SimpleXMLElement）＃5（1）{[＆＃34; @ attributes＆＃34;] =＆gt; array（7）{[＆＃34; delivery＆＃34;] =＆gt; string（11）＆＃34; progressive＆＃34; [＆＃34;类型＆＃34;] =＆GT; string（9）＆＃34; video / mp4＆＃34; [＆＃34;宽度＆＃34;] =＆GT;字符串（3）＆＃34; 640＆＃34; [＆＃34;高度＆＃34;] =＆GT; string（3）＆＃34; 360＆＃34; [＆＃34;比特率＆＃34;] =＆GT; string（3）＆＃34; 500＆＃34; [＆＃34;可伸缩＆＃34;] =＆GT; string（4）＆＃34; true＆＃34; [＆＃34; maintainAspectRatio＆＃34;] =＆GT; string（4）＆＃34; true＆＃34; object（SimpleXMLElement）＃4（1）{[＆＃34; @ attributes＆＃34;] =＆gt; array（7）{[＆＃34; delivery＆＃34;] =＆gt; string（11）＆＃34; progressive＆＃34; [＆＃34;类型＆＃34;] =＆GT; string（9）＆＃34; video / mp4＆＃34; [＆＃34;宽度＆＃34;] =＆GT; string（3）＆＃34; 320＆＃34; [＆＃34;高度＆＃34;] =＆GT; string（3）＆＃34; 180＆＃34; [＆＃34;比特率＆＃34;] =＆GT; string（3）＆＃34; 500＆＃34; [＆＃34;可伸缩＆＃34;] =＆GT; string（4）＆＃34; true＆＃34; [＆＃34; maintainAspectRatio＆＃34;] =＆GT; string（4）＆＃34; true＆＃34; }}

提前感谢您的帮助。

Answer 1

您需要使用显式类型转换来获取CDATA内容：
的var_dump（的（字符串） $文件）;

$xml = <<<XML <VAST version="3.0"> <MediaFiles> <MediaFile delivery="progressive" type="video/mp4" width="640" height="360" bitrate="500" scalable="true" maintainAspectRatio="true"> <![CDATA[ https://appnext-a.akamaihd.net/banner/video/video-192347-30_o.mp4?rnd=1488986809 ]]> </MediaFile> <MediaFile delivery="progressive" type="video/mp4" width="320" height="180" bitrate="500" scalable="true" maintainAspectRatio="true"> <![CDATA[ https://appnext-a.akamaihd.net/banner/video/video-192347-30.mp4?rnd=1488986813 ]]> </MediaFile> </MediaFiles> </VAST> XML; $response = simplexml_load_string($xml); $files = $response->MediaFiles->MediaFile; foreach ($files as $file) { var_dump((string)$file); }

https://3v4l.org/Rl6q1#output

simplexml_load_string访问标记值

1 个答案: