sql pivot with dynamic columns我在这里附上了我对表和数据的查询，
/****** Object: Table [dbo].[Company] Script Date: 13/04/2017 3:37:15 PM ******/
CREATE TABLE [dbo].[Company](
[Comp ID] [int] NULL,
[Company Name] [nvarchar](50) NULL
) ON [PRIMARY]
GO
/****** Object: Table [dbo].[Designation] Script Date: 13/04/2017 3:37:15 PM ******/
CREATE TABLE [dbo].[Designation](
[Design ID] [int] NULL,
[Comp ID] [int] NULL,
[Designation] [nvarchar](50) NULL,
[Design Code] [int] NULL
) ON [PRIMARY]
GO
/****** Object: Table [dbo].[Employee] Script Date: 13/04/2017 3:37:15 PM ******/
CREATE TABLE [dbo].[Employee](
[Emp ID] [int] NULL,
[Comp ID] [int] NULL,
[Design ID] [int] NULL,
[Employee Name] [nvarchar](50) NULL,
[Employee Code] [int] NULL
) ON [PRIMARY]
GO
INSERT [dbo].[Company] ([Comp ID], [Company Name]) VALUES (1, N'Company 1')
GO
INSERT [dbo].[Company] ([Comp ID], [Company Name]) VALUES (2, N'Company 2')
GO
INSERT [dbo].[Designation] ([Design ID], [Comp ID], [Designation], [Design Code]) VALUES (1, 1, N'CEO', 2)
GO
INSERT [dbo].[Designation] ([Design ID], [Comp ID], [Designation], [Design Code]) VALUES (2, 1, N'HR', 1)
GO
INSERT [dbo].[Designation] ([Design ID], [Comp ID], [Designation], [Design Code]) VALUES (3, 2, N'CEO', 1)
GO
INSERT [dbo].[Designation] ([Design ID], [Comp ID], [Designation], [Design Code]) VALUES (3, 2, N'Developer', 2)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (1, 1, 1, N'Test emp1', 101)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (2, 1, 1, N'Test emp2', 102)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (3, 1, 2, N'Test emp3', 103)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (4, 1, 2, N'Test emp4', 104)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (5, 1, 1, N'Test emp5', 105)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (6, 1, 2, N'Test emp6', 106)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (7, 2, 1, N'Test emp7', 107)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (8, 2, 1, N'Test emp8', 108)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (9, 2, 2, N'Test emp9', 109)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (10, 2, 2, N'Test emp10', 110)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (11, 2, 1, N'Test emp11', 111)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (12, 2, 1, N'Test emp12', 112)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (13, 1, 1, N'Test emp13', 113)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (14, 1, 2, N'Test emp14', 114)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (15, 2, 1, N'Test emp15', 115)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (16, 2, 2, N'Test emp16', 116)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (17, 1, 1, N'Test emp17', 117)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (18, 1, 2, N'Test emp18', 118)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (19, 2, 1, N'Test emp19', 119)
GO
INSERT [dbo].[Employee] ([Emp ID], [Comp ID], [Design ID], [Employee Name], [Employee Code]) VALUES (20, 2, 2, N'Test emp20', 120)
GO
我有3个表作为公司，指定，员工
我需要一个查询，为所有公司订购最新指定（设计代码）的最新4名员工（按员工代码排序），然后按照设计代码的降序，然后按员工代码的降序选择，并为每家公司选择前4名记录 结果需要像
那样透视例如：
CompanyID Emp1 Emp2 Emp3 Emp4
----------
1 118 114 106 103
我尝试了类似的东西，
select
emp.[Comp ID],
emp.[Design ID],
emp.[Emp ID],
emp.[Employee Code],
design.[Design Code],
emp.[Employee Code],
comp.[Company Name],
design.Designation,
emp.[Employee Name]
from Employee emp
join Designation design on design.[Design ID]=emp.[Design ID]
join Company comp on comp.[Comp ID]=emp.[Comp ID]
order by comp.[Comp ID] desc, design.[Design Code] desc, emp.[Employee Code] desc
我需要前4名员工为emp1，emp2，emp3和emp4转换为每个公司，有可能2个可能属于一个名称，3个来自其他和相同的员工代码可以重复使用不同的公司代码，它需要按公司代码排序，然后按员工代码排序
答案 0 :(得分：1)
希望这就是你要找的东西，
SELECT [comp id],
emp1,
emp2,
emp3,
emp4
FROM (SELECT [comp id],
[employee code],
'Emp' + Cast(rn AS CHAR(10)) AS Empname
FROM (SELECT A.[comp id],
A.[employee code],
Row_number()
OVER (
partition BY A.[comp id]
ORDER BY B.[comp id], C.[design code]
DESC, A.[employee code] DESC)
AS rn
FROM dbo.employee A
INNER JOIN dbo.company B
ON A.[comp id] = B.[comp id]
INNER JOIN dbo.designation C
ON C.[design code] = A.[design id]
AND C.[comp id] = B.[comp id])A
WHERE rn <= 4)B
PIVOT ( Max([employee code])
FOR empname IN (emp1,
emp2,
emp3,
emp4) ) pv
结果如下所示，
comp id emp1 emp2 emp3 emp4
1 118 114 106 104
2 120 116 110 109
注意：根据我的理解
答案 1 :(得分：0)
试试这样：
function SearchGrid(txtSearchSAP, grdSapDetails) {
if ($("[id *=" + txtSearchSAP + " ]").val() != "") {
var count = 0;
$("[id *=" + grdSapDetails + " ]").children
('tbody').children('tr').each(function () {
$(this).show();
});
$("[id *=" + grdSapDetails + " ]").children
('tbody').children('tr').each(function () {
var match = false;
$(this).children('td').each(function () {
if ($(this).text().toUpperCase().indexOf($("[id *=" +
txtSearchSAP + " ]").val().toUpperCase()) > -1) {
match = true;
count++;
return false;
}
});
if (match) {
$(this).show();
$(this).children('th').show();
}
else {
$(this).hide();
$(this).children('th').show();
}
});
$("[id *=" + grdSapDetails + " ]").children('tbody').
children('tr').each(function (index) {
if (index == 0)
{
$(this).show();
}
});
if(count==0)
{
alert("No Matching Records");
}
}
else {
$("[id *=" + grdSapDetails + " ]").children('tbody').
children('tr').each(function () {
$(this).show();
count=0;
});
}
}
$(document).on("keyup", function () {
SearchGrid('txtSearchSAP', 'grdSapDetails');
});