Question

任何帮助都将受到赞赏：在我弄清楚我做错了之前，我无法继续前进..

我正在使用for循环在某些文本中搜索名称，然后尝试将这些字母推送到数组中。由于某种原因，它不是推动，我不确定我做错了什么..仍然是一个新的... thx的帮助！

var text = "Code it out bro, it will just get Zane Zane Zane better 
from here, especially after your familiar with the various 
frameworks..yeah man...";
var hits = [ ];
var nameZane = "Zane";
for (i=0; i < text.length; i++) 
if (i === "Z"){
    for (j=i; j < nameZane.length + i; j++){
    hits.push(text[j])}
}

if (hits.length === 0){
    console.log("Couldn't find " + nameZane)}
else{
    console.log(hits)}

Answer 1

如果条件i

，text[i]不是if (text[i] === "Z") {使用此

var text = "Code it out bro, it will just get Zane Zane Zane better from here, especially after your familiar with the variousframeworks..yeah man...";
var hits = [];
var nameZane = "Zane";
for (i = 0; i < text.length; i++)
  if (text[i] === "Z") {
    for (j = i; j < nameZane.length + i; j++) {
      hits.push(text[j])
    }
  }

if (hits.length == 0) {
  console.log("What the f*** man?")
} else {
  console.log(hits)
}

Update  fp
 set fp.Address_Id=al.AddressID_new
  from [dbo].[fact_P]  fp join AddressLookup al
      on fp.Address_Id= al.AddressID_old

Answer 2

编辑您的代码：
if (i === "Z")到

if (text.charAt(i) == 'Z')

AND

hits.push(text[j])

到

hits.push(text.charAt(j));

Answer 3

var re = /Zane/g,
str = "Code it out bro, it will just get Zane Zane Zane better from here, especially after your familiar with the various frameworks..yeah man...";
while ((match = re.exec(str)) != null) {
    console.log("match found at " + match.index);
}

在文本中搜索名称（javascript）

3 个答案: