Question

def number_of_cases(list_data):
    from itertools import combinations_with_replacement
    mylist = list_data
    result = list(combinations_with_replacement(mylist, 2))
    return(result)

def main():
    result = number_of_cases(['a', 'b'])
    print(result)

结果：

>>> main()
[('a', 'a'), ('a', 'b'), ('b', 'b')]

我不希望组合之间有任何空间......如下所示.. 如何为以下结果创建代码？

>>> a = ['a', 'b', 'c']
['aa', 'ab', 'ac', 'ba', 'bb', 'bc', 'ca', 'cb', 'cc']'

>>> a = ['a', 'a']
['aa']

>>> a = [1, 2, 3, 'a']
['11', '12', '13', '1a', '21', '22', '23', '2a', '31', '32', '33', '3a', 'a1', 'a2', 'a3', 'aa']

Answer 1

你需要str（）元素将它们全部作为字符串，然后加入结果列表的每个元素。

def number_of_cases(list_data):
     from itertools import combinations_with_replacement
     list_data = [str(data) for data in list_data]
     mylist=list_data
     result=list(combinations_with_replacement(mylist,2))
     joined_result = []
     for choice in result:
           joined = ''.join(choice)
           joined_result.append(joined)
     return(joined_result)

def main():
     result=number_of_cases(['a','b'])
     print(result)

['aa'，'ab'，'bb']

如何为结果创建代码？

1 个答案: