Question

升级上面的jar文件后，我一直遇到以下问题：

org.springframework.beans.factory.BeanCreationException：The ＆＃39; currentComponent＆＃39; （org.springframework.integration.router.MethodInvokingRouter@5ddcc487）是一个单向的MessageHandler＆＃39;并且它不适合配置＆＃39; outputChannel＆＃39 ;.这是整合流程的结束。在 org.springframework.integration.dsl.IntegrationFlowDefinition.registerOutputChannelIfCan（IntegrationFlowDefinition.java:3053）在 org.springframework.integration.dsl.IntegrationFlowDefinition.register（IntegrationFlowDefinition.java:2994）在 org.springframework.integration.dsl.IntegrationFlowDefinition.handle（IntegrationFlowDefinition.java:1167）在 org.springframework.integration.dsl.IntegrationFlowDefinition.handle（IntegrationFlowDefinition.java:987）在 org.springframework.integration.dsl.IntegrationFlowDefinition.handle（IntegrationFlowDefinition.java:964）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests（RemoteTestRunner.java:459）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests（RemoteTestRunner.java:678）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run（RemoteTestRunner.java:382）在 org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main（RemoteTestRunner.java:192）

代码段：

public IntegrationFlow inBoundFlow(ConnectionFactory mqConnection)
    throws JMSException {

    return IntegrationFlows
            .from(Jms.messageDrivenChannelAdapter(mqConnection)
                    .configureListenerContainer(listenerContainer)
                    .destination(mqProperties.getQueue().getRequest())
                    .errorChannel(ErrorChannel())
                    .setHeaderMapper(new DefaultJmsHeaderMapper()))
            .filter(filterMessage, "filterMessage", m -> m.discardChannel(DiscardChannel()))
            .route(mqMessageRouter, "messageRouter")
            .handle(errorChannel, "handleError")
            .get();
}


@Named
public class MQErrorMessageChannel {

    @ServiceActivator(inputChannel = MQ_ERROR_MESSAGE_INPUT_CHANNEL, outputChannel = MQ_ERROR_MESSAGE_OUTPUT_CHANNEL)
    public Message<String> handleError(Throwable t) {
//Do Something....
        }
        return null;
    }
}

任何指针？

Answer 1

此方法调用形式中的.route(mqMessageRouter, "messageRouter")完全是单向，您无法在流程中指出任何内容。

没有严格的决定在路由器之后接下来哪个频道，所以我们无法从那里继续流动。

只需将流量分成几个，然后将.handle()添加到每个特定的路由流中。

Spring Integration和DSL升级 - 单向＆＃39; MessageHandler＆＃39;并且配置＆quot; outputChannel＆＃39;是不合适的。错误

1 个答案: